Math Problem Statement

Suppose z varies inversely with t and that z = 9 when t = 11. What is the value of z when t = 3?

Solution

To solve this problem, let's break down the concept of inverse variation and apply it step-by-step.

Step 1: Understanding Inverse Variation

When zz varies inversely with tt, it means: z=ktz = \frac{k}{t} where kk is a constant.

Step 2: Finding the Constant kk

We are given that z=9z = 9 when t=11t = 11. Substitute these values into the equation to find kk: 9=k119 = \frac{k}{11} Multiplying both sides by 11 to isolate kk: k=9×11=99k = 9 \times 11 = 99

Step 3: Using the Constant to Find zz When t=3t = 3

Now, we know k=99k = 99, so we can use the inverse variation formula again: z=99tz = \frac{99}{t} Substitute t=3t = 3: z=993=33z = \frac{99}{3} = 33

Final Answer

z=33z = 33

Would you like a further explanation on inverse variation, or do you have any questions?


Here are 5 related questions to explore further:

  1. What would the value of zz be if t=5t = 5?
  2. How would the equation change if zz varied directly with tt instead of inversely?
  3. If z=33z = 33 when t=3t = 3, what would tt be when z=22z = 22?
  4. How can we determine if a relationship is inverse or direct variation?
  5. What happens to the value of zz as tt approaches infinity?

Tip: In inverse variation, as one variable increases, the other decreases. This property is helpful in identifying inverse relationships.

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Math Problem Analysis

Mathematical Concepts

Inverse Variation
Algebra

Formulas

z = k/t

Theorems

Inverse Variation Theorem

Suitable Grade Level

Grades 8-10