Math Problem Statement

The function f left parenthesis x right parenthesis equals 2 x plus 7 is​ one-to-one.

a. Find an equation for f Superscript negative 1​, the inverse function.

b. Verify that your equation is correct by showing that f left parenthesis f Superscript negative 1 Baseline left parenthesis x right parenthesis right parenthesisequalsx and f Superscript negative 1 Baseline left parenthesis f left parenthesis x right parenthesis right parenthesisequalsx.

Question content area bottom

Part 1

a. Select the correct choice below and fill in the answer​ box(es) to complete your choice.

​(Simplify your answer. Use integers or fractions for any numbers in the​ expression.)

A.

f Superscript negative 1 Baseline left parenthesis x right parenthesisequals    enter your response here​, for xnot equals    enter your response here

B.

f Superscript negative 1 Baseline left parenthesis x right parenthesisequals    enter your response here​, for xless than or equals    enter your response here

C.

f Superscript negative 1 Baseline left parenthesis x right parenthesisequals    enter your response here​, for xgreater than or equals    enter your response here

D.

f Superscript negative 1 Baseline left parenthesis x right parenthesisequals    enter your response here​, for all x

Solution

Part 1a: Finding the Inverse Function

The function given is f(x)=2x+7f(x) = 2x + 7. To find the inverse function, follow these steps:

  1. Replace f(x)f(x) with yy: y=2x+7y = 2x + 7

  2. Swap xx and yy (this is the key step to finding the inverse): x=2y+7x = 2y + 7

  3. Solve for yy: x7=2yx - 7 = 2y y=x72y = \frac{x - 7}{2}

Thus, the inverse function is: f1(x)=x72f^{-1}(x) = \frac{x - 7}{2}

Part 1b: Verifying the Inverse Function

To verify that f1(x)=x72f^{-1}(x) = \frac{x - 7}{2} is correct, we need to check two conditions:

  1. f(f1(x))=xf(f^{-1}(x)) = x:

    Substitute f1(x)f^{-1}(x) into f(x)f(x): f(f1(x))=f(x72)f(f^{-1}(x)) = f\left( \frac{x - 7}{2} \right) Using the original function f(x)=2x+7f(x) = 2x + 7: f(x72)=2(x72)+7=(x7)+7=xf\left( \frac{x - 7}{2} \right) = 2\left( \frac{x - 7}{2} \right) + 7 = (x - 7) + 7 = x So, f(f1(x))=xf(f^{-1}(x)) = x.

  2. f1(f(x))=xf^{-1}(f(x)) = x:

    Substitute f(x)=2x+7f(x) = 2x + 7 into f1(x)f^{-1}(x): f1(f(x))=f1(2x+7)=(2x+7)72=2x2=xf^{-1}(f(x)) = f^{-1}(2x + 7) = \frac{(2x + 7) - 7}{2} = \frac{2x}{2} = x So, f1(f(x))=xf^{-1}(f(x)) = x.

Both conditions are satisfied, confirming that f1(x)=x72f^{-1}(x) = \frac{x - 7}{2} is the correct inverse function.

Answer Choice:

The correct answer is: f1(x)=x72, for all x.\boxed{f^{-1}(x) = \frac{x - 7}{2}, \text{ for all } x.}


Would you like further clarification or details on any step?

5 Related Questions:

  1. What are the general steps to finding an inverse of a linear function?
  2. How can you verify if a function is one-to-one before finding its inverse?
  3. Why is it necessary to swap xx and yy when finding an inverse function?
  4. Can a function have an inverse if it is not one-to-one? Why or why not?
  5. How would the process change if the function were not linear?

Tip:

To ensure a function is one-to-one, check that it passes the horizontal line test, meaning no horizontal line intersects the graph more than once.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Inverse Functions
Linear Functions

Formulas

Inverse function formula f^(-1)(x) = (x - b) / a for linear functions
Verification formulas: f(f^(-1)(x)) = x and f^(-1)(f(x)) = x

Theorems

Properties of Inverse Functions
One-to-one Function Theorem

Suitable Grade Level

Grades 10-12