Math Problem Statement

the function f(x)=\sqrt[4]{7x} is one to one. find an equation for f^{-1}\left(x\right), the inverse function

Solution

To find the inverse function f1(x)f^{-1}(x) of f(x)=7x4f(x) = \sqrt[4]{7x}, follow these steps:

  1. Express the function in terms of yy: y=7x4y = \sqrt[4]{7x}

  2. Solve for xx in terms of yy: To eliminate the fourth root, raise both sides to the power of 4: y4=7xy^4 = 7x Now, solve for xx: x=y47x = \frac{y^4}{7}

  3. Interchange xx and yy: Since we are looking for the inverse function, switch xx and yy: y=x47y = \frac{x^4}{7}

Thus, the inverse function is: f1(x)=x47f^{-1}(x) = \frac{x^4}{7}

Do you have any questions or want further details?

Here are 5 related questions to explore:

  1. How do you verify if a function is one-to-one?
  2. What is the significance of finding the inverse of a function?
  3. Can all functions have inverses?
  4. How do domain restrictions affect the inverse function?
  5. How would the process change if the function had a different root or power?

Tip: To check if two functions are truly inverses, apply both compositions f(f1(x))f(f^{-1}(x)) and f1(f(x))f^{-1}(f(x)). They should return xx.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Radical Functions
Algebra

Formulas

f(x) = \sqrt[4]{7x}
f^{-1}(x) = \frac{x^4}{7}

Theorems

One-to-One Function Theorem
Inverse Function Theorem

Suitable Grade Level

Grades 10-12