Math Problem Statement

find the inverse of the function f(x)=x^5-3/2

Solution

To find the inverse of the function f(x)=x532f(x) = x^5 - \frac{3}{2}, we need to follow these steps:

  1. Rewrite the function using yy instead of f(x)f(x):

    y=x532y = x^5 - \frac{3}{2}

  2. Swap xx and yy to begin finding the inverse:

    x=y532x = y^5 - \frac{3}{2}

  3. Solve for yy (which will give us f1(x)f^{-1}(x)):

    • First, isolate the y5y^5 term by adding 32\frac{3}{2} to both sides:

      x+32=y5x + \frac{3}{2} = y^5

    • Now, solve for yy by taking the fifth root of both sides:

      y=x+325y = \sqrt[5]{x + \frac{3}{2}}

Thus, the inverse function is:

f1(x)=x+325f^{-1}(x) = \sqrt[5]{x + \frac{3}{2}}

Let me know if you'd like a more detailed explanation or if you have any questions!

5 Related Questions:

  1. What is the domain and range of f(x)=x532f(x) = x^5 - \frac{3}{2}?
  2. How do we verify that two functions are inverses of each other?
  3. What is the difference between an inverse function and a reciprocal function?
  4. How do the graphs of f(x)f(x) and f1(x)f^{-1}(x) compare?
  5. Can all functions be inverted? If not, why?

Tip:

Always check that the inverse function returns the original value when plugged back into the original function to confirm its correctness.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Exponents
Algebraic Manipulation

Formulas

f(x) = x^5 - 3/2
f^{-1}(x) = \sqrt[5]{x + 3/2}

Theorems

Inverse Function Theorem

Suitable Grade Level

Grades 10-12