Math Problem Statement

What is the inverse function of the f(x) = x/2?

f−1(x) = 2x

f−1(x) = x/2

f−1(x) = x + 2

f−1(x) = x − 2

f−1(x) = 2x + 2

Solution

Let's find the inverse function of f(x)=x2f(x) = \frac{x}{2}.

To find the inverse, we need to solve for xx in terms of yy (where y=f(x)y = f(x)):

  1. Start with the equation: y=x2y = \frac{x}{2}

  2. Now, solve for xx: x=2yx = 2y

  3. Since we are finding the inverse, replace yy with xx (the variable for the inverse function): f1(x)=2xf^{-1}(x) = 2x

So the correct inverse function is f1(x)=2xf^{-1}(x) = 2x.

Answer:

The inverse function is f1(x)=2xf^{-1}(x) = 2x.

Would you like more explanation on inverse functions or have any other questions? Here are some related questions you may find interesting:

  1. How do we verify the correctness of an inverse function?
  2. How do we find the inverse of a function that involves powers or square roots?
  3. What does the graph of a function and its inverse look like?
  4. How can we determine if a function is one-to-one, and why does it matter for finding an inverse?
  5. What is the composition of a function and its inverse? How do we prove they are inverses?

Tip: To check if two functions are true inverses, try composing them (i.e., f(f1(x))=xf(f^{-1}(x)) = x and f1(f(x))=xf^{-1}(f(x)) = x)!

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Math Problem Analysis

Mathematical Concepts

Algebra
Inverse Functions

Formulas

f(x) = x/2
f^{-1}(x) = 2x

Theorems

Inverse function theorem

Suitable Grade Level

Grades 8-10