Math Problem Statement

The function f left parenthesis x right parenthesis equals x cubed plus 8

is​ one-to-one. ​(a) Find the inverse of f and check the answer. ​(b) Find the domain and the range of f and f Superscript negative 1 . ​(c) Graph​ f, f Superscript negative 1 ​, and yequals x on the same coordinate axes. Question content area bottom left Part 1 ​(a) f Superscript negative 1 Baseline left parenthesis x right parenthesis equalsenter your response here ​(Simplify your answer. Use integers or fractions for any numbers in the​ expression.)

Solution

Let's break down the problem step by step:

Part (a) - Finding the inverse of f(x)=x3+8f(x) = x^3 + 8

To find the inverse, we start by expressing yy as a function of xx:

y=x3+8y = x^3 + 8

Now, solve for xx in terms of yy:

  1. Subtract 8 from both sides: y8=x3y - 8 = x^3

  2. Take the cube root of both sides: x=y83x = \sqrt[3]{y - 8}

Thus, the inverse function f1(x)f^{-1}(x) is:

f1(x)=x83f^{-1}(x) = \sqrt[3]{x - 8}

Checking the answer

We can verify that the inverse is correct by performing the following checks:

  1. Compute f(f1(x))f(f^{-1}(x)): [ f(f^{-1}(x)) = f(\sqrt[3]{x - 8}) = (\sqrt[3]{x - 8})^3 + 8 = x - 8 + 8 = x ]

  2. Compute f1(f(x))f^{-1}(f(x)): [ f^{-1}(f(x)) = f^{-1}(x^3 + 8) = \sqrt[3]{(x^3 + 8) - 8} = \sqrt[3]{x^3} = x ]

Both compositions yield xx, confirming that the inverse is correct.

Part (b) - Domain and Range

  • The domain of f(x)=x3+8f(x) = x^3 + 8 is all real numbers, (,)(-\infty, \infty), because cubic functions are defined for all real values of xx.

  • The range of f(x)=x3+8f(x) = x^3 + 8 is also all real numbers, (,)(-\infty, \infty), since cubic functions cover all real values as xx increases or decreases without bound.

For the inverse function f1(x)=x83f^{-1}(x) = \sqrt[3]{x - 8}:

  • The domain of f1(x)f^{-1}(x) is (,)(-\infty, \infty), since the cube root function is defined for all real values of xx.

  • The range of f1(x)f^{-1}(x) is also (,)(-\infty, \infty), as the cube root function can output any real number.

Part (c) - Graphing f(x)f(x), f1(x)f^{-1}(x), and y=xy = x

To graph these functions:

  1. Graph f(x)=x3+8f(x) = x^3 + 8, a cubic function shifted upward by 8 units.
  2. Graph f1(x)=x83f^{-1}(x) = \sqrt[3]{x - 8}, which is the reflection of f(x)f(x) over the line y=xy = x.
  3. Plot the line y=xy = x as a reference.

Would you like me to generate the graph for you?


Do you have any questions or want further details?

Here are 5 related questions:

  1. How would the inverse function change if f(x)=x38f(x) = x^3 - 8?
  2. Can you explain why the inverse of a cubic function is also one-to-one?
  3. What happens to the domain and range of a function when you reflect it over the line y=xy = x?
  4. Why do cubic functions always have a domain and range of all real numbers?
  5. How would the graph change if we had f(x)=x3+cf(x) = x^3 + c where cc is any constant?

Tip: Inverse functions reflect the original function over the line y=xy = x, which means the x-values and y-values swap places.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Cubic Functions
Graphing
Domain and Range

Formulas

f(x) = x^3 + 8
f⁻¹(x) = ³√(x - 8)
Composition of Functions: f(f⁻¹(x)) and f⁻¹(f(x))

Theorems

Inverse Function Theorem
Properties of Cubic Functions

Suitable Grade Level

Grades 10-12