Math Problem Statement

The intervals where f(x)>0 for x^4-2x^3-3x^2

Solution

To find the intervals where f(x)>0f(x) > 0 for the function f(x)=x42x33x2f(x) = x^4 - 2x^3 - 3x^2, we need to determine the regions where the function is positive. Here are the steps:

  1. Factor the function: First, factor f(x)f(x) completely.

f(x)=x42x33x2=x2(x22x3)f(x) = x^4 - 2x^3 - 3x^2 = x^2(x^2 - 2x - 3)

Now, factor the quadratic expression:

x22x3=(x3)(x+1)x^2 - 2x - 3 = (x - 3)(x + 1)

So, the fully factored form is:

f(x)=x2(x3)(x+1)f(x) = x^2 (x - 3) (x + 1)

  1. Find the critical points: Set f(x)=0f(x) = 0 to find the critical points.

x2(x3)(x+1)=0x^2 (x - 3) (x + 1) = 0

This gives:

x=0,x=3,x=1x = 0, \quad x = 3, \quad x = -1

  1. Determine the sign of f(x)f(x) in each interval: We will test the sign of f(x)f(x) in the intervals determined by the critical points: (,1)(-\infty, -1), (1,0)(-1, 0), (0,3)(0, 3), and (3,)(3, \infty).
  • For x(,1)x \in (-\infty, -1): Choose x=2x = -2.

    f(2)=(2)2×(23)×(2+1)=4×(5)×(1)=20(positive)f(-2) = (-2)^2 \times (-2 - 3) \times (-2 + 1) = 4 \times (-5) \times (-1) = 20 \quad (\text{positive})

  • For x(1,0)x \in (-1, 0): Choose x=0.5x = -0.5.

    f(0.5)=(0.5)2×(0.53)×(0.5+1)=0.25×(3.5)×0.5=0.4375(negative)f(-0.5) = (-0.5)^2 \times (-0.5 - 3) \times (-0.5 + 1) = 0.25 \times (-3.5) \times 0.5 = -0.4375 \quad (\text{negative})

  • For x(0,3)x \in (0, 3): Choose x=1x = 1.

    f(1)=12×(13)×(1+1)=1×(2)×2=4(negative)f(1) = 1^2 \times (1 - 3) \times (1 + 1) = 1 \times (-2) \times 2 = -4 \quad (\text{negative})

  • For x(3,)x \in (3, \infty): Choose x=4x = 4.

    f(4)=42×(43)×(4+1)=16×1×5=80(positive)f(4) = 4^2 \times (4 - 3) \times (4 + 1) = 16 \times 1 \times 5 = 80 \quad (\text{positive})

  1. Identify the intervals where f(x)>0f(x) > 0:

From the analysis:

  • f(x)>0f(x) > 0 in the intervals (,1)(-\infty, -1) and (3,)(3, \infty).

Therefore, the intervals where f(x)>0f(x) > 0 are:

(,1)(3,)(-\infty, -1) \cup (3, \infty)

Would you like more details or have any questions?

Here are some related questions:

  1. How do we find the intervals where f(x)<0f(x) < 0?
  2. What are the turning points of f(x)=x42x33x2f(x) = x^4 - 2x^3 - 3x^2?
  3. How can we sketch the graph of f(x)=x42x33x2f(x) = x^4 - 2x^3 - 3x^2?
  4. What is the behavior of f(x)f(x) as xx approaches infinity?
  5. How do we determine the local minima and maxima of f(x)f(x)?

Tip: To check where a polynomial is positive or negative, factor it completely and test the sign of each factor in the intervals determined by the roots!

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Functions
Factorization
Inequalities

Formulas

Factoring a polynomial: f(x) = x^4 - 2x^3 - 3x^2 = x^2(x - 3)(x + 1)

Theorems

Sign of a product in intervals determined by roots

Suitable Grade Level

Grades 10-12