Math Problem Statement

Complete parts (a) through (c) for the function f(x) = -3x^3 + 3x^2 - x - 1. Part (a): Find intervals where the function is increasing or decreasing, and determine any relative extrema.

Solution

Let's analyze the given function f(x)=3x3+3x2x1f(x) = -3x^3 + 3x^2 - x - 1 to solve part (a), where we need to find intervals where the function is increasing or decreasing and determine any relative extrema.

Step 1: Find the first derivative f(x)f'(x)

To determine the intervals of increase or decrease, we first find the derivative of the function:

f(x)=ddx(3x3+3x2x1)f'(x) = \frac{d}{dx} (-3x^3 + 3x^2 - x - 1)

f(x)=9x2+6x1f'(x) = -9x^2 + 6x - 1

Step 2: Find critical points

To find the critical points, set the first derivative equal to zero:

9x2+6x1=0-9x^2 + 6x - 1 = 0

Solve this quadratic equation using the quadratic formula:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

where a=9a = -9, b=6b = 6, and c=1c = -1.

x=6±624(9)(1)2(9)x = \frac{-6 \pm \sqrt{6^2 - 4(-9)(-1)}}{2(-9)} x=6±363618x = \frac{-6 \pm \sqrt{36 - 36}}{-18} x=6±018x = \frac{-6 \pm 0}{-18} x=618=13x = \frac{-6}{-18} = \frac{1}{3}

So, the only critical point is x=13x = \frac{1}{3}.

Step 3: Test intervals around the critical point

We now test the intervals around x=13x = \frac{1}{3} to determine where the function is increasing or decreasing.

  • For x<13x < \frac{1}{3}, choose x=0x = 0: f(0)=9(0)2+6(0)1=1f'(0) = -9(0)^2 + 6(0) - 1 = -1 Since f(0)<0f'(0) < 0, the function is decreasing on (,13)(-\infty, \frac{1}{3}).

  • For x>13x > \frac{1}{3}, choose x=1x = 1: f(1)=9(1)2+6(1)1=9+61=4f'(1) = -9(1)^2 + 6(1) - 1 = -9 + 6 - 1 = -4 Since f(1)<0f'(1) < 0, the function is also decreasing on (13,)(\frac{1}{3}, \infty).

Step 4: Conclusion for part (a)

The function is decreasing on the entire real line, except for the critical point where there is no increase. Therefore, the answer is:

  • The function is decreasing on (,)(-\infty, \infty).

Thus, option C: "The function is decreasing on (,)(-\infty, \infty) and increasing nowhere" is the correct choice.


Would you like to proceed with part (b) for concavity and inflection points, or do you have any questions? Here are 5 related questions to practice:

  1. What does the first derivative of a function tell you about its graph?
  2. How can you determine the concavity of a function using the second derivative?
  3. What is the significance of critical points in the graph of a function?
  4. How do you classify relative extrema using the first derivative test?
  5. Can a function be both increasing and concave down at the same time? Why or why not?

Tip: Always test values around critical points to determine whether the function is increasing or decreasing in each interval.

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Math Problem Analysis

Mathematical Concepts

Calculus
First Derivative Test
Critical Points
Increasing and Decreasing Intervals

Formulas

First derivative: f'(x) = -9x^2 + 6x - 1
Quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

Theorems

First Derivative Test

Suitable Grade Level

Grades 11-12 (or introductory college calculus)