Math Problem Statement

f(x)=-3x^3+10x^2+9x-4

  1. bestem, ved aflæsning af grafen, monotoniforhold, ekstrema og krumningsforhold for f

Solution

To analyze the function f(x)=3x3+10x2+9x4f(x) = -3x^3 + 10x^2 + 9x - 4 and determine the monotonicity, extrema, and concavity, let's proceed with each step:

1. Monotonicity

Monotonicity refers to where the function is increasing or decreasing. To analyze this, we need the first derivative, f(x)f'(x), and find its sign over different intervals.

First Derivative:

f(x)=9x2+20x+9f'(x) = -9x^2 + 20x + 9

To find where the function changes from increasing to decreasing (or vice versa), set f(x)=0f'(x) = 0: 9x2+20x+9=0-9x^2 + 20x + 9 = 0 This is a quadratic equation in xx, and solving it gives us the critical points.

Solving f(x)=0f'(x) = 0:

Use the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} where a=9a = -9, b=20b = 20, and c=9c = 9. Calculating this, we get: x=20±400+32418x = \frac{-20 \pm \sqrt{400 + 324}}{-18} x3 and x13x \approx 3 \text{ and } x \approx -\frac{1}{3}

These points divide the x-axis into intervals. By testing the sign of f(x)f'(x) in each interval, we can determine if f(x)f(x) is increasing or decreasing in each interval.

2. Extrema

The critical points found above (where f(x)=0f'(x) = 0) are potential extrema. We check the values of f(x)f(x) at these points to determine whether they are local maxima or minima.

  • If f(x)f'(x) changes from positive to negative at a critical point, it's a local maximum.
  • If f(x)f'(x) changes from negative to positive, it's a local minimum.

By substituting values around x3x \approx 3 and x13x \approx -\frac{1}{3}, we determine the nature of each extremum.

3. Concavity and Inflection Points

To analyze concavity, we use the second derivative f(x)f''(x).

Second Derivative:

f(x)=18x+20f''(x) = -18x + 20

Setting f(x)=0f''(x) = 0 gives the inflection point(s), where the concavity changes.

18x+20=0-18x + 20 = 0 x=2018=1091.11x = \frac{20}{18} = \frac{10}{9} \approx 1.11

At x1.11x \approx 1.11, the concavity of f(x)f(x) changes:

  • If f(x)>0f''(x) > 0 to the left of x=1.11x = 1.11, the function is concave up.
  • If f(x)<0f''(x) < 0 to the right of x=1.11x = 1.11, the function is concave down.

Summary

  • Monotonicity: Determine intervals of increase/decrease using f(x)f'(x).
  • Extrema: Evaluate f(x)f(x) at critical points to find local maxima or minima.
  • Concavity: Use f(x)f''(x) to determine intervals of concave up/down and identify inflection points.

Would you like a more detailed analysis or a graph of these findings?


Further Exploration Questions

  1. How would the graph change if the coefficient of x3x^3 were positive?
  2. How does the second derivative test help determine concavity?
  3. Could we approximate extrema and inflection points without calculus? If so, how?
  4. What real-world scenarios might this cubic function model?
  5. How would the function behave as xx \to \infty or xx \to -\infty?

Tip:

Analyzing the signs of the first and second derivatives on intervals can quickly give insights into the function's behavior.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Differentiation
Monotonicity
Extrema
Concavity
Cubic Functions

Formulas

First Derivative: f'(x) = -9x^2 + 20x + 9
Second Derivative: f''(x) = -18x + 20
Quadratic Formula: x = (-b ± √(b² - 4ac)) / 2a

Theorems

First Derivative Test
Second Derivative Test

Suitable Grade Level

Grades 11-12