Math Problem Statement
What is the interquartile range for the following 12,5,22,30,7,36,14,42,15,53,25,65
Solution
To find the interquartile range (IQR), follow these steps:
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Order the data in ascending order:
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Find the median (Q2):
- There are 12 numbers, so the median is the average of the 6th and 7th numbers.
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Find the lower quartile (Q1):
- The lower quartile is the median of the lower half (first 6 numbers): The median of this set is the average of the 3rd and 4th numbers.
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Find the upper quartile (Q3):
- The upper quartile is the median of the upper half (last 6 numbers): The median of this set is the average of the 3rd and 4th numbers.
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Calculate the interquartile range (IQR):
So, the interquartile range (IQR) is 26.
Would you like more details or have any questions?
Here are 5 related questions:
- How do you interpret the IQR in terms of data spread?
- What does a larger IQR indicate about data variability?
- Can outliers be detected using IQR?
- How do quartiles help in understanding the distribution of data?
- How is IQR different from the range?
Tip: The IQR is useful because it is not affected by extreme values or outliers, unlike the total range.
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Math Problem Analysis
Mathematical Concepts
Descriptive Statistics
Quartiles
Interquartile Range
Formulas
Median: (n+1)/2-th value for odd sets, average of two central values for even sets
Lower Quartile (Q1): Median of the lower half of the data
Upper Quartile (Q3): Median of the upper half of the data
Interquartile Range (IQR) = Q3 - Q1
Theorems
Quartile Theorem
Interquartile Range Theorem
Suitable Grade Level
Grades 9-11
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