Math Problem Statement

intregation of a(e^x)+b(e^x)

Solution

To integrate the expression aex+bexa e^x + b e^x, we can factor out exe^x, as both terms contain this factor. The integration process becomes:

(aex+bex)dx\int (a e^x + b e^x) \, dx

Factor out exe^x:

=ex(a+b)dx= \int e^x (a + b) \, dx

Since a+ba + b is just a constant, you can take it outside of the integral:

=(a+b)exdx= (a + b) \int e^x \, dx

The integral of exe^x is simply exe^x, so we get:

=(a+b)ex+C= (a + b) e^x + C

where CC is the constant of integration.

Thus, the result is:

(a+b)ex+C\boxed{(a + b) e^x + C}

Would you like further details or have any specific questions about this process?

Here are a few questions that might help expand on this topic:

  1. What would happen if the integral had a different base, like e2xe^{2x}?
  2. How would you handle integrals involving constants that are not factored out, like aex+ba e^x + b?
  3. Could you explain how to solve an integral like eaxdx\int e^{ax} \, dx?
  4. How does the method of integration change when there are products involving polynomials and exponentials?
  5. What is the general rule for integrating exponential functions?

Tip: When you encounter sums in an integral, you can always split them up into separate integrals, as long as they are within the same limits of integration.

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Math Problem Analysis

Mathematical Concepts

Integration
Exponential Functions

Formulas

\int e^x dx = e^x + C
\int (a e^x + b e^x) dx = (a + b) e^x + C

Theorems

Constant Multiple Rule of Integration

Suitable Grade Level

Grades 11-12