Math Problem Statement

integrate 1/a^2+x^2

Solution

We are asked to evaluate the integral:

1a2+x2dx\int \frac{1}{a^2 + x^2} \, dx

This is a standard integral, and it can be solved using the following formula:

1a2+x2dx=1atan1(xa)+C\int \frac{1}{a^2 + x^2} \, dx = \frac{1}{a} \tan^{-1} \left( \frac{x}{a} \right) + C

where aa is a constant and CC is the constant of integration.

Thus, the result of the given integral is:

1atan1(xa)+C\frac{1}{a} \tan^{-1} \left( \frac{x}{a} \right) + C

Would you like further clarification or more details on any steps?

Here are 5 related questions to explore further:

  1. How can this integral be applied in real-world problems?
  2. What is the geometric interpretation of the arctangent function in this context?
  3. How does the result change if aa is a function of xx?
  4. Can we apply substitution techniques to solve similar integrals?
  5. What are the differences between this and the integral 1a2x2dx\int \frac{1}{a^2 - x^2} \, dx?

Tip: For integrals involving quadratic terms like a2+x2a^2 + x^2, trigonometric substitution often simplifies the problem.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Calculus
Integration
Inverse Trigonometric Functions

Formulas

∫ 1/(a^2 + x^2) dx = (1/a) * tan^(-1)(x/a) + C

Theorems

Inverse Trigonometric Integration

Suitable Grade Level

Undergraduate Calculus