Math Problem Statement

Can you do the 6 steps and show the work please

Can you do the 6 steps and show the work please?

Solution

To solve these integrals using u-substitution, we will go through the standard 6 steps:

  1. Choose the substitution u=f(x)u = f(x)
  2. Find the derivative of uu (i.e., dudu)
  3. Rewrite the integral in terms of uu
  4. Perform the integration in terms of uu
  5. Substitute back u=f(x)u = f(x)
  6. Simplify the result

Let's solve the integrals step-by-step:

(a) (x2+2x(2x+2))dx\int \left( \sqrt{x^2 + 2x} \cdot (2x + 2) \right) \, dx

Step 1: Choose the substitution.

  • We will choose the expression inside the square root as uu. Let u=x2+2xu = x^2 + 2x.

Step 2: Find the derivative of uu (i.e., dudu).

  • Differentiate u=x2+2xu = x^2 + 2x with respect to xx: du=(2x+2)dxdu = (2x + 2) \, dx So, 2x+2dx=du2x + 2 \, dx = du, which is exactly what we have in the integrand.

Step 3: Rewrite the integral in terms of uu.

  • Substitute u=x2+2xu = x^2 + 2x and du=(2x+2)dxdu = (2x + 2) \, dx: (x2+2x(2x+2))dx=udu\int \left( \sqrt{x^2 + 2x} \cdot (2x + 2) \right) dx = \int \sqrt{u} \, du

Step 4: Perform the integration in terms of uu.

  • The integral of u=u1/2\sqrt{u} = u^{1/2} is: u1/2du=23u3/2+C\int u^{1/2} \, du = \frac{2}{3} u^{3/2} + C

Step 5: Substitute back u=x2+2xu = x^2 + 2x.

  • Now replace uu with x2+2xx^2 + 2x: 23(x2+2x)3/2+C\frac{2}{3} (x^2 + 2x)^{3/2} + C

Step 6: Simplify the result.

  • The final answer for part (a) is: 23(x2+2x)3/2+C\frac{2}{3} (x^2 + 2x)^{3/2} + C

(b) (cosxesinx)dx\int \left( \frac{\cos x}{e^{\sin x}} \right) dx

Step 1: Choose the substitution.

  • Let u=sinxu = \sin x, since cosx\cos x is the derivative of sinx\sin x.

Step 2: Find the derivative of uu (i.e., dudu).

  • Differentiate u=sinxu = \sin x: du=cosxdxdu = \cos x \, dx So, cosxdx=du\cos x \, dx = du.

Step 3: Rewrite the integral in terms of uu.

  • Substitute u=sinxu = \sin x and du=cosxdxdu = \cos x \, dx: cosxesinxdx=1eudu\int \frac{\cos x}{e^{\sin x}} \, dx = \int \frac{1}{e^u} \, du

Step 4: Perform the integration in terms of uu.

  • The integral of 1eu=eu\frac{1}{e^u} = e^{-u} is: eudu=eu+C\int e^{-u} \, du = -e^{-u} + C

Step 5: Substitute back u=sinxu = \sin x.

  • Now replace uu with sinx\sin x: esinx+C-e^{-\sin x} + C

Step 6: Simplify the result.

  • The final answer for part (b) is: esinx+C-e^{-\sin x} + C

Would you like more details on any step or clarification on the concepts? Here are 5 related questions to deepen your understanding:

  1. How do you choose the right substitution in u-substitution problems?
  2. What is the relationship between integration by parts and u-substitution?
  3. Can all integrals be solved using u-substitution, or are there exceptions?
  4. How does u-substitution simplify more complex integrals?
  5. How do constants of integration factor into definite integrals with u-substitution?

Tip: When choosing a substitution, look for functions within the integrand whose derivative is also present (or nearly present) elsewhere in the integrand.

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Math Problem Analysis

Mathematical Concepts

u-substitution
integrals
differentiation
integration

Formulas

Substitution: u = f(x)
Derivative of u: du = f'(x) dx
Integral of u^n: ∫ u^n du = (1/(n+1)) * u^(n+1) + C

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

Grades 11-12