Math Problem Statement

Find or evaluate the integral. (Use C for the constant of integration.) xe8x dx

Solution

We need to evaluate the integral:

xe8xdx\int x e^{8x} \, dx

This requires integration by parts, which uses the formula:

udv=uvvdu\int u \, dv = uv - \int v \, du

Step 1: Assign uu and dvdv

Let: u=xanddv=e8xdxu = x \quad \text{and} \quad dv = e^{8x} dx

Now, compute dudu and vv: du=dxandv=18e8xdu = dx \quad \text{and} \quad v = \frac{1}{8} e^{8x}

Step 2: Apply the Integration by Parts Formula

Substitute into the formula: xe8xdx=uvvdu\int x e^{8x} dx = uv - \int v \, du

xe8xdx=x18e8x18e8xdx\int x e^{8x} dx = x \cdot \frac{1}{8} e^{8x} - \int \frac{1}{8} e^{8x} dx

Step 3: Simplify the Expression

The first term is: x8e8x\frac{x}{8} e^{8x}

The remaining integral is: 18e8xdx=1818e8x=164e8x\int \frac{1}{8} e^{8x} dx = \frac{1}{8} \cdot \frac{1}{8} e^{8x} = \frac{1}{64} e^{8x}

Thus, the solution becomes: xe8xdx=x8e8x164e8x+C\int x e^{8x} dx = \frac{x}{8} e^{8x} - \frac{1}{64} e^{8x} + C

Final Answer:

xe8xdx=x8e8x164e8x+C\int x e^{8x} dx = \frac{x}{8} e^{8x} - \frac{1}{64} e^{8x} + C

Would you like a detailed breakdown of any specific step or have any questions?

Related Questions:

  1. How is the formula for integration by parts derived?
  2. Can this integral be solved without using integration by parts?
  3. What is the importance of the constant of integration?
  4. How does integration by parts differ from substitution methods?
  5. Can integration by parts be applied recursively? What are some examples?

Tip:

When choosing uu and dvdv for integration by parts, prioritize selecting uu as a term that simplifies upon differentiation!

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Math Problem Analysis

Mathematical Concepts

Calculus
Integration by Parts
Exponential Functions

Formulas

Integration by parts formula: ∫u dv = uv - ∫v du
Exponential function integral: ∫e^(ax) dx = (1/a)e^(ax) + C

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

College Level or Advanced High School (Grades 11-12)