https://file.aiquickdraw.com/mathbot/file/1730115985117kairtwdx.jpg

The integral in the image is:

\[
\int (2x - 1) \, dx
\]

To solve it, we can integrate each term separately:

1. For the term \(2x\): The integral of \(2x\) with respect to \(x\) is \(\int 2x \, dx = x^2\).
2. For the term \(-1\): The integral of \(-1\) with respect to \(x\) is \(\int -1 \, dx = -x\).

Thus, combining these results:

\[
\int (2x - 1) \, dx = x^2 - x + C
\]

where \(C\) is the constant of integration.

### Final Answer:
\[
x^2 - x + C
\]

Would you like more details on the integration process, or have any questions?

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Here are 5 related questions:
1. How would you integrate \( \int (3x - 4) \, dx \)?
2. What is the integral of \( \int (x^2 - 3x + 5) \, dx \)?
3. How do you handle integrals involving exponential functions, like \( \int e^{2x} \, dx \)?
4. What is the integral of \( \int (2x + \sin x) \, dx \)?
5. How would you compute a definite integral for \( \int_{1}^{3} (2x - 1) \, dx \)?

**Tip:** When integrating, separate terms if possible to make integration easier term by term.

Learn how to find the integral of (2x - 1) with a detailed step-by-step solution. This example covers key calculus concepts and provides an easy approach to integrating polynomial functions. Suitable for high school students in Grades 10-12.

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