Math Problem Statement

Evaluate the integral ∫ (x^3 / √(x^2 + 5)) dx.

Solution

The integral presented is:

x3x2+5dx\int \frac{x^3}{\sqrt{x^2 + 5}} \, dx

Steps to solve:

  1. Substitution: Use u=x2+5u = x^2 + 5, which simplifies the square root.

    • Then, du=2xdxdu = 2x \, dx, or du2=xdx\frac{du}{2} = x \, dx.
  2. Rewriting x3x^3 in terms of uu:

    • Notice that x3=xx2=x(u5)x^3 = x \cdot x^2 = x \cdot (u - 5), so: x3=x(u5)x^3 = x(u - 5)
  3. Substituting into the integral: x3x2+5dx=x(u5)udu2\int \frac{x^3}{\sqrt{x^2 + 5}} \, dx = \int \frac{x(u - 5)}{\sqrt{u}} \cdot \frac{du}{2}

  4. Breaking it into two simpler integrals: =12(u5)u12du= \frac{1}{2} \int (u - 5) u^{-\frac{1}{2}} \, du =12(u12du5u12du)= \frac{1}{2} \left( \int u^{\frac{1}{2}} \, du - 5 \int u^{-\frac{1}{2}} \, du \right)

  5. Solving these integrals:

    • u12du=23u32\int u^{\frac{1}{2}} \, du = \frac{2}{3} u^{\frac{3}{2}}
    • u12du=2u12\int u^{-\frac{1}{2}} \, du = 2 u^{\frac{1}{2}}
  6. Putting everything together: 12(23u3252u12)\frac{1}{2} \left( \frac{2}{3} u^{\frac{3}{2}} - 5 \cdot 2 u^{\frac{1}{2}} \right) =13u325u12= \frac{1}{3} u^{\frac{3}{2}} - 5 u^{\frac{1}{2}}

  7. Substitute back u=x2+5u = x^2 + 5: =13(x2+5)325(x2+5)12+C= \frac{1}{3} (x^2 + 5)^{\frac{3}{2}} - 5 (x^2 + 5)^{\frac{1}{2}} + C

Thus, the solution to the integral is:

13(x2+5)325(x2+5)12+C\frac{1}{3} (x^2 + 5)^{\frac{3}{2}} - 5 (x^2 + 5)^{\frac{1}{2}} + C

Would you like further details or have any questions?

Here are 5 related questions for practice:

  1. How does substitution simplify integrals involving square roots?
  2. What are the common techniques for solving integrals of this type?
  3. Can you apply similar substitution methods to trigonometric integrals?
  4. What is the geometric interpretation of integrals like this one?
  5. How does the choice of substitution affect the simplicity of the solution?

Tip: When dealing with square roots and powers of variables in integrals, substitution is a powerful tool for simplification!

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Math Problem Analysis

Mathematical Concepts

Calculus
Integration
Substitution

Formulas

u-substitution formula: ∫ f(g(x))g'(x) dx = ∫ f(u) du
Integration of powers: ∫ u^n du = (u^(n+1)) / (n+1) + C, where n ≠ -1

Theorems

Substitution theorem for integrals

Suitable Grade Level

College Calculus