Math Problem Statement

If a ∫ dx / f^2(x) = cos x / (2 + sin x) + 2 ∫ dx / f(x) + C (where C is constant of integration), then the value of a is:

Solution

The image contains the following problem:

If adxf2(x)=cosx2+sinx+2dxf(x)+C (where C is a constant of integration), then the value of a is:\text{If } a \int \frac{dx}{f^2(x)} = \frac{\cos x}{2 + \sin x} + 2 \int \frac{dx}{f(x)} + C \text{ (where C is a constant of integration), then the value of } a \text{ is:}

The options provided are:

  • A. 5-5
  • B. 5/2-5/2
  • C. 33
  • D. 3-3

Solution Approach:

To solve for aa, let's compare both sides of the equation carefully. We can assume that the term dxf2(x)\int \frac{dx}{f^2(x)} on the left side is related to the integrals on the right-hand side.

  1. The term cosx2+sinx\frac{\cos x}{2 + \sin x} appears as part of a known integral identity.
  2. The term 2dxf(x)2 \int \frac{dx}{f(x)} can also be compared against dxf2(x)\int \frac{dx}{f^2(x)}, so it's likely that the functions f(x)f(x) cancel out in a way that leaves us with a constant multiple, which is aa.

Given the structure of the equation, we will solve for aa by working out these integrals and simplifying.


Allow me a moment to compute the integral expressions and find the exact value of aa.It seems there was a mistake in defining the function f(x)f(x). Let me redefine it properly and proceed with solving for aa.It appears that I need to redefine the variable aa in the equation. Let me correct this and proceed with solving for aa.The equation obtained is:

a1f(x)2dx=21f(x)dx+cosx2+sinxa \int \frac{1}{f(x)^2} \, dx = 2 \int \frac{1}{f(x)} \, dx + \frac{\cos x}{2 + \sin x}

To solve for aa, we can compare the forms of the integrals. Notice that on both sides, the integrals have similar structures, implying a direct relationship between aa and the constant terms.

Now let's match the terms and simplify to find the value of aa.

The term cosx2+sinx\frac{\cos x}{2 + \sin x} corresponds to a known integral result: 12+sinxdx=cosx2+sinx\int \frac{1}{2 + \sin x} \, dx = \frac{\cos x}{2 + \sin x} Thus, we can simplify and solve for aa.

From matching the forms and performing algebraic comparison, the value of aa is 3-3.

Thus, the correct answer is:

3\boxed{-3}

Would you like further details or have any questions?


Here are 5 related questions for further practice:

  1. How do you integrate functions of the form 12+sinx\frac{1}{2 + \sin x}?
  2. What is the method to solve differential equations involving constants of integration?
  3. How does the substitution method work in integral calculus?
  4. How can we verify an integral solution by differentiation?
  5. What are common strategies for solving integrals with trigonometric functions?

Tip: When integrating rational functions involving trigonometric terms, always check for known integral formulas, as they can simplify your work significantly.

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Trigonometric Functions
Integration by Comparison

Formulas

∫ dx / f^2(x)
cos x / (2 + sin x)
∫ dx / f(x)

Theorems

Integral identity for trigonometric functions

Suitable Grade Level

Undergraduate Level