Math Problem Statement
Solution
To solve the integral
we proceed as follows:
Step 1: Distribute the terms
Expand the product inside the integral:
Step 2: Simplify the first term
Using the identity :
Step 3: Simplify the second term
Recall the derivative of : Thus: This simplifies to:
Step 4: Combine results
Combining the results from both parts: where is the constant of integration.
Would you like further clarification or details on any of the steps? Here are some related questions for further exploration:
- What are the key hyperbolic function identities used in integrals?
- How does the derivative of relate to this integral?
- Can substitution techniques simplify integrals involving hyperbolic functions further?
- What are practical applications of hyperbolic integrals in physics or engineering?
- How does the integration process differ for definite integrals of similar functions?
Tip: Memorize basic hyperbolic function derivatives and identities—they often simplify complex integrals.
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Math Problem Analysis
Mathematical Concepts
Hyperbolic Functions
Integral Calculus
Simplification of Expressions
Formulas
cosh(t) · sech(t) = 1
Derivative of coth(t): d/dt(coth(t)) = -csch²(t)
Theorems
Properties of Hyperbolic Functions
Fundamental Theorem of Calculus
Suitable Grade Level
Undergraduate (Calculus II or III)
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