Math Problem Statement

The sides of an inscribed angle intercept the circle at the endpoints of the diameter. What is the measure of the angle?

Solution

Let’s work through the problems provided in the image step-by-step.


Questions 18–20

18. The sides of an inscribed angle intercept the circle at the endpoints of the diameter.
Answer: 90°.
Reason: An inscribed angle subtending the diameter always measures 90° because it forms a right angle.

19. Quadrilateral ABCDABCD is inscribed in O\bigodot O. If mA=70°m\angle A = 70°, find mCm\angle C.
Answer: 110°.
Reason: Opposite angles of an inscribed quadrilateral sum to 180°. Thus, mC=180°70°=110°m\angle C = 180° - 70° = 110°.

20. If inscribed angles ABCABC and ADCADC both intercept \overarcAC\overarc{AC}, which measures 120°, find mABCm\angle ABC and mADCm\angle ADC.
Answer: mABC=60°m\angle ABC = 60°, mADC=60°m\angle ADC = 60°.
Reason: An inscribed angle is half the measure of its intercepted arc. Therefore, mABC=mADC=12(120°)=60°m\angle ABC = m\angle ADC = \frac{1}{2}(120°) = 60°.


Proof of mB=12mAOCm\angle B = \frac{1}{2}m\angle AOC

Let’s fill out the missing steps in the proof table:

  1. BC\overline{BC} is a diameter of O\bigodot O; AB\overline{AB} is any other chord.
    Reason: Given.

  2. Draw radius OA\overline{OA}.
    Reason: Definition of radius.

  3. mA+mB=mAOCm\angle A + m\angle B = m\angle AOC.
    Reason: The angles add up because they share the arc \overarcAC\overarc{AC}.

  4. All radii of O\bigodot O are congruent.
    Reason: Radii of a circle are equal (Postulate 21).

  5. OAB\triangle OAB is isosceles.
    Reason: Isosceles Triangle Theorem.

  6. mA=mBm\angle A = m\angle B.
    Reason: Base angles of an isosceles triangle are congruent.

  7. mB+mB=mAOCm\angle B + m\angle B = m\angle AOC.
    Reason: Substituting mA=mBm\angle A = m\angle B from Step 6.

  8. mB=12mAOCm\angle B = \frac{1}{2}m\angle AOC.
    Reason: Divide both sides by 2.

  9. m\overarcAC=mAOCm\overarc{AC} = m\angle AOC.
    Reason: Central angle theorem.

  10. Substitution Property: mB=12m\overarcACm\angle B = \frac{1}{2}m\overarc{AC}.
    Reason: Substitution from Step 8.


Let me know if you want further clarification or step-by-step details! Here are 5 related questions to practice:

  1. What is the relationship between a central angle and an inscribed angle intercepting the same arc?
  2. How do you prove that opposite angles in an inscribed quadrilateral sum to 180°?
  3. How can the diameter of a circle help identify inscribed right triangles?
  4. Explain why mABC=mADCm\angle ABC = m\angle ADC when both intercept the same arc.
  5. Why do all radii of a circle have equal lengths?

Tip: Always visualize circle properties like radii, diameters, and intercepted arcs to simplify proofs and problems!

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Math Problem Analysis

Mathematical Concepts

Geometry
Circle Theorems
Inscribed Angles

Formulas

Inscribed angle subtending the diameter = 90°

Theorems

Inscribed Angle Theorem

Suitable Grade Level

Grades 9-10