To determine which equation has infinitely many solutions, we need to simplify the given equations and check for identities.

The equations you provided can be interpreted as:

1. Equation 1: $5z + 42(26) = 3(2 - 3) - 9z + 6$
2. Equation 2: $7z - 17(21) = 5z + 46(22)$

Simplifying Each Equation

Equation 1: $5z + 42 \cdot 26 = 3(-1) - 9z + 6$ Calculating the constants: $5z + 1092 = -3 - 9z + 6$ $5z + 1092 = 3 - 9z$ Rearranging gives: $5z + 9z = 3 - 1092$ $14z = -1089$ $z = -\frac{1089}{14}$

This equation has a unique solution.

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Equation 2: $7z - 17 \cdot 21 = 5z + 46 \cdot 22$ Calculating the constants: $7z - 357 = 5z + 1012$ Rearranging gives: $7z - 5z = 1012 + 357$ $2z = 1369$ $z = \frac{1369}{2}$

This equation also has a unique solution.

Conclusion

Since neither equation leads to a statement that holds true for all $z$, neither has infinitely many solutions. To have infinitely many solutions, the equations must reduce to a true statement, like $0 = 0$.

If you meant to ask about a different set of equations or if you have further questions, please clarify!

Questions for Further Exploration:

1. Can you provide more equations to analyze?
2. What criteria do you use to determine if an equation has infinitely many solutions?
3. Would you like an explanation of how to solve systems of equations?
4. Are you interested in understanding the concept of dependent and independent equations?
5. Do you want to learn about how to identify equations that have no solutions?

Tip:

Always check if rearranging the terms can reveal if two expressions are equivalent, leading to infinite solutions.