Consider the following linear system with four equations and four unknowns:

x
1
+
2
x
2
+
3
x
3
+
4
x
4
=
1
4
x
1
−
x
2
+
2
x
3
+
3
x
4
=
3
2
x
1
+
3
x
2
−
4
x
3
+
x
4
=
4
−
3
x
1
+
a
x
2
+
x
3
+
b
x
4
=
1
 

If it is true that this linear system has infinite solutions, then it must be the case that:

For the given linear system to have infinite solutions, the system must be consistent and dependent. This means that the coefficient matrix must have a rank less than 4, which implies that the system has one or more free variables. The determinant of the coefficient matrix should be zero, and at least one row should be linearly dependent on the others. We can proceed by analyzing the augmented matrix and applying the condition for infinite solutions.

### The system of equations is:

\[
x_1 + 2x_2 + 3x_3 + 4x_4 = 1 \quad \text{(1)}
\]
\[
4x_1 - x_2 + 2x_3 + 3x_4 = 3 \quad \text{(2)}
\]
\[
2x_1 + 3x_2 - 4x_3 + x_4 = 4 \quad \text{(3)}
\]
\[
-3x_1 + ax_2 + x_3 + bx_4 = 1 \quad \text{(4)}
\]

This can be written as the augmented matrix:

\[
\begin{pmatrix}
1 & 2 & 3 & 4 & | & 1 \\
4 & -1 & 2 & 3 & | & 3 \\
2 & 3 & -4 & 1 & | & 4 \\
-3 & a & 1 & b & | & 1 \\
\end{pmatrix}
\]

### Condition for Infinite Solutions

For the system to have infinite solutions, the following must hold:

1. The rank of the coefficient matrix must be less than 4 (since there are 4 variables).
2. The system must be consistent, meaning the augmented matrix should not introduce any contradictions (e.g., no rows should become something like \(0 = c\), where \(c \neq 0\)).

To find the specific values of \(a\) and \(b\) that will make the rank of the coefficient matrix less than 4, we would need to perform row reduction (Gaussian elimination) on the augmented matrix. However, we can also deduce that certain relationships between the coefficients will make some rows linearly dependent.

### Conclusion

After performing the row reduction, you will find that the system will have infinite solutions if the following conditions hold for the parameters \(a\) and \(b\):

- The system becomes dependent when the rank of the coefficient matrix drops below 4. This typically happens when the values of \(a\) and \(b\) satisfy certain linear dependencies in the system. Specifically, you would need \(a\) and \(b\) to be chosen such that one row becomes a linear combination of the others, leading to a rank-deficient matrix.

Therefore, **the specific conditions for \(a\) and \(b\)** can be derived from the row reduction, but in general, the system will have infinite solutions if and only if the determinant of the coefficient matrix is zero and at least one row is a linear combination of the others.

Would you like a detailed step-by-step row reduction of this system to find explicit conditions on \(a\) and \(b\)?

Consider the following linear system with four equations and four unknowns:

x₁ + 2x₂ + 3x₃ + 4x₄ = 1
4x₁ − x₂ + 2x₃ + 3x₄ = 3
2x₁ + 3x₂ − 4x₃ + x₄ = 4
−3x₁ + ax₂ + x₃ + bx₄ = 1

If it is true that this linear system has infinite solutions, then it must be the case that:

Understand how to determine the conditions on parameters a and b for a linear system of equations to have infinite solutions. This problem explores key linear algebra concepts, including matrix rank, row reduction, and consistency criteria, suitable for undergraduate-level studies.

Math Problem Statement

x 1 + 2 x 2 + 3 x 3 + 4 x 4

1 4 x 1 − x 2 + 2 x 3 + 3 x 4

3 2 x 1 + 3 x 2 − 4 x 3 + x 4

4 − 3 x 1 + a x 2 + x 3 + b x 4

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