Math Problem Statement

b) Let open interval An = ( − 1 n , n ) . Find ⋂∞ i=1 Ai and ⋃∞ i=1 Ai

Solution

Given the open intervals An=(1n,n)A_n = \left(-\frac{1}{n}, n\right), we need to find:

  1. The intersection of all these intervals: i=1Ai\bigcap_{i=1}^{\infty} A_i.
  2. The union of all these intervals: i=1Ai\bigcup_{i=1}^{\infty} A_i.

1. Finding i=1Ai\bigcap_{i=1}^{\infty} A_i

The intersection of the intervals An=(1n,n)A_n = \left(-\frac{1}{n}, n\right) involves finding the set of points that belong to all AnA_n as nn tends to infinity.

As nn increases, 1n-\frac{1}{n} gets closer to 0 from the left, and nn increases without bound. Therefore, for every point xx in the intersection:

  • The point must satisfy x>1nx > -\frac{1}{n} for all nn. In the limit as nn \to \infty, this means x0x \geq 0.
  • Simultaneously, the point must satisfy x<nx < n for all nn, but this is always true for finite xx since nn is unbounded.

Thus, the only value that can be in every AnA_n is x=0x = 0.

i=1Ai={0}\bigcap_{i=1}^{\infty} A_i = \{0\}

2. Finding i=1Ai\bigcup_{i=1}^{\infty} A_i

The union of the intervals An=(1n,n)A_n = \left(-\frac{1}{n}, n\right) involves finding the set of points that belong to at least one AnA_n.

As nn increases:

  • The lower bound 1n-\frac{1}{n} approaches 0 from the left, meaning any negative number slightly less than 0 will eventually be included in some AnA_n.
  • The upper bound nn grows without bound, meaning all positive numbers will be included as well.

Thus, the union of all intervals covers all real numbers:

i=1Ai=R\bigcup_{i=1}^{\infty} A_i = \mathbb{R}

Final Answers

  1. i=1Ai={0}\bigcap_{i=1}^{\infty} A_i = \{0\}
  2. i=1Ai=R\bigcup_{i=1}^{\infty} A_i = \mathbb{R}

Would you like more details or have any questions?

Here are some related questions to consider:

  1. What happens if the interval was An=(1n,1n)A_n = \left(-\frac{1}{n}, \frac{1}{n}\right)?
  2. How does the intersection change if the intervals are closed instead of open?
  3. What if the intervals were of the form An=(0,1n)A_n = \left(0, \frac{1}{n}\right)?
  4. How would the results differ if An=(n,1n)A_n = \left(-n, \frac{1}{n}\right)?
  5. What is the significance of the result in terms of measure theory?

Tip: When dealing with infinite intersections, consider how the endpoints behave as nn changes to understand the limiting behavior.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Real Analysis
Limits
Infinite Intervals

Formulas

Intersection of intervals: ⋂∞ i=1 Ai
Union of intervals: ⋃∞ i=1 Ai

Theorems

Concept of infinite intersection and union
Limit behavior of intervals as n approaches infinity

Suitable Grade Level

College Level (Advanced Calculus or Real Analysis)