Math Problem Statement
Solution
Let's analyze and solve both of the problems from the image:
Problem 4:
Prove that:
Solution:
- First, observe that the intersection is over open intervals , which are defined for each . The intervals expand as increases.
- For , the interval is , which includes all numbers between and .
- For , the interval is , which is smaller than the previous interval.
- As increases, the intervals shrink and approach . More formally, the endpoints of the intervals, and , approach 0 and 1 as .
Thus, the intersection of all these intervals for to infinity will be the closed interval . Therefore, we have:
Problem 5:
Prove that if is a family of sets and , then .
Solution:
- Let be a family of sets, and .
- The union is the set of all elements that belong to at least one of the sets in . Since , all elements of are also elements of the union.
- Formally, for every , since , we have .
Therefore, .
Do you want further details on these proofs or have any questions? Here are five related questions to deepen understanding:
- What is the significance of using open intervals in Problem 4?
- Can you generalize Problem 4 for any interval ?
- How would the proof in Problem 5 change if ?
- Can you give an example of a family of sets to illustrate Problem 5?
- What are some practical applications of intersections and unions of sets in real life?
Tip: In proofs involving intervals, always check how the boundaries behave as changes to ensure the correct interval limits.
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Math Problem Analysis
Mathematical Concepts
Set Theory
Real Analysis
Intervals
Intersection and Union of Sets
Formulas
[0, 1] = ⋂_{n=1}^{∞} ( -1/n, 1 + 1/n)
B ⊆ ⋃_{A ∈ A} A
Theorems
Convergence of intervals
Basic set theory operations (intersection and union)
Suitable Grade Level
Undergraduate mathematics or advanced high school