Math Problem Statement

Give me independent t test data to solve

Solution

Here’s a set of data you can use for solving an independent t-test problem:

Problem Statement:

Two different teaching methods are being tested for their effectiveness in improving student test scores. A sample of 10 students is selected from each group, and their scores on a standardized test are recorded. The data for both groups is as follows:

Group 1 (Traditional Teaching Method):

StudentScore
182
290
385
488
579
684
787
891
983
1089

Group 2 (New Teaching Method):

StudentScore
175
278
374
482
580
676
777
879
973
1081

Hypothesis:

  • Null Hypothesis (H₀): There is no significant difference in the average test scores between the two teaching methods.
  • Alternative Hypothesis (H₁): There is a significant difference in the average test scores between the two teaching methods.

You are asked to:

  1. Perform an independent t-test to determine if there is a statistically significant difference in the mean test scores between the two groups.
  2. Use a significance level of 0.05.

Would you like to proceed with solving this t-test, or would you like additional guidance or clarification on how to approach it?

Here are some related questions:

  1. What is the formula for calculating the independent t-test?
  2. How do you calculate the degrees of freedom for an independent t-test?
  3. What assumptions are made in an independent t-test?
  4. How do you interpret the p-value from an independent t-test?
  5. What is the difference between a one-tailed and two-tailed t-test?

Tip: Remember to check the assumptions of the t-test, particularly the assumption of equal variances between the two groups, before proceeding with the test.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Hypothesis Testing
Independent T-Test

Formulas

t = (X̄1 - X̄2) / √[(s1^2/n1) + (s2^2/n2)]
Degrees of freedom: df = n1 + n2 - 2

Theorems

Central Limit Theorem
T-Distribution Properties

Suitable Grade Level

Grades 11-12, Undergraduate