Math Problem Statement

( ) 4 6 5 1 1 4 2 1 2 1 2 1 6 5 x x dx x x C − = − + − + ∫

Solution

It looks like you're presenting an integral equation, but the formatting might be a bit unclear. Let me break it down and clarify the expression to help with solving it.

From what I understand, this equation looks like an indefinite integral:

(6x54x4+2x3x2+1)dx\int (6x^5 - 4x^4 + 2x^3 - x^2 + 1) \, dx

Where the expression inside the integral is:

6x54x4+2x3x2+16x^5 - 4x^4 + 2x^3 - x^2 + 1

You also mentioned a constant CC, which is common for indefinite integrals.

To solve the integral, we'll integrate each term separately. Here's the step-by-step process:

Step 1: Integrate each term

6x5dx=6x66=x6\int 6x^5 \, dx = \frac{6x^6}{6} = x^6 4x4dx=4x55=4x55\int -4x^4 \, dx = \frac{-4x^5}{5} = -\frac{4x^5}{5} 2x3dx=2x44=x42\int 2x^3 \, dx = \frac{2x^4}{4} = \frac{x^4}{2} x2dx=x33\int -x^2 \, dx = \frac{-x^3}{3} 1dx=x\int 1 \, dx = x

Step 2: Combine the results

So the integral becomes: x64x55+x42x33+x+Cx^6 - \frac{4x^5}{5} + \frac{x^4}{2} - \frac{x^3}{3} + x + C

Thus, the solution to your integral is:

(6x54x4+2x3x2+1)dx=x64x55+x42x33+x+C\int (6x^5 - 4x^4 + 2x^3 - x^2 + 1) \, dx = x^6 - \frac{4x^5}{5} + \frac{x^4}{2} - \frac{x^3}{3} + x + C

Let me know if you'd like further clarification or have any other questions!


Related Questions:

  1. How do I solve integrals involving trigonometric functions?
  2. What are the rules for integrating exponential functions?
  3. Can you explain the difference between indefinite and definite integrals?
  4. How do I handle rational functions in integrals?
  5. What is the importance of the constant CC in an indefinite integral?

Tip: When solving integrals, always remember to apply the power rule for polynomials and keep track of the constants for each term.

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Indefinite Integrals
Polynomial Integration

Formulas

Integral of x^n = x^(n+1) / (n+1) + C

Theorems

Power Rule for Integration
Indefinite Integral Theorem

Suitable Grade Level

Grades 11-12