Math Problem Statement
Solution
Let’s go through each problem in detail.
Problem 56
Question: Find the maximum angle of inclination that an inclined plane could have without a block on it sliding if the coefficient of friction is 0.3.
To solve this:
- The angle of inclination where an object is just about to slide can be found using: where (coefficient of friction).
- Thus,
- Calculating this yields approximately: So, the answer is b. 16.7°.
Problem 57
Question: A 2 N weight is swinging in a vertical circle of 1 m radius, and the cable will break if the tension exceeds 500 N. What is the angular velocity when the cable breaks?
To solve this:
- The maximum tension in the cable occurs at the lowest point and is given by:
where:
- (breaking tension),
- (weight),
- ,
- is the angular velocity we need to find.
- Rearrange to solve for :
- Simplifying, So, the closest answer is a. 15.8 rad/sec.
Problem 58
Question: Two men race around a circular track 1200 meters long. If they run in opposite directions and meet every 3 minutes, what is the velocity of the slower man if the faster runs at 200 m/min?
To solve this:
- Let (velocity of the faster runner), and be the velocity of the slower runner.
- Since they meet every 3 minutes, their combined speed relative to each other is:
- Solving for : So, the answer is b. 200 m/min.
Would you like a deeper explanation for any of these solutions or have any specific questions?
Here are five related questions for further exploration:
- How would the solution to Problem 56 change if the coefficient of friction were increased?
- Can you derive the formula used in Problem 57 for maximum tension in a rotating object?
- In Problem 58, what if the runners were moving in the same direction? How would that affect the answer?
- How does changing the radius in Problem 57 affect the angular velocity at which the cable would break?
- In Problem 56, how would reducing the mass of the block impact the maximum angle?
Tip: For inclined planes, remember that the frictional force limits the angle at which sliding begins. This force is a product of the normal force and the coefficient of friction.
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Math Problem Analysis
Mathematical Concepts
Physics
Circular motion
Trigonometry
Relative speed
Formulas
tan(theta) = mu
T = mg + m * omega^2 * r
Relative velocity formula for circular motion
Theorems
Angle of inclination based on friction
Centripetal force in circular motion
Suitable Grade Level
Grade 10-12
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