Math Problem Statement

Identify the surface in R^3: 1. The surface r = 4cos(θ) is a circle and the equation in rectangular coordinates is x^2 + y^2 = 4x. 2. The surface z = sqrt(3x^2 + 3y^2) is a cone and the equation in spherical coordinates is φ = π/6.

Solution

Let's analyze the two questions in the uploaded image step-by-step.

1. Surface r=4cos(θ)r = 4 \cos(\theta):

  • This equation is given in polar coordinates.
  • Type of surface: This describes a circle in the 2D xyxy-plane (more specifically, a shifted circle).
  • To convert it to rectangular coordinates:
    1. Use the identities: r2=x2+y2,x=rcos(θ)r^2 = x^2 + y^2, \quad x = r \cos(\theta)
    2. Substituting r=4cos(θ)r = 4 \cos(\theta): x=4cos(θ)    x2+y2=4xx = 4 \cos(\theta) \implies x^2 + y^2 = 4x
    • Answer in rectangular coordinates:
      x2+y2=4xx^2 + y^2 = 4x
      (This equation describes a circle centered at (2,0)(2, 0) with radius 2.)

2. Surface z=3x2+3y2z = \sqrt{3x^2 + 3y^2}:

  • Type of surface: This describes a cone.

    • Since the zz-value is proportional to the square root of x2+y2x^2 + y^2, the shape forms a cone symmetric around the zz-axis.
  • Spherical coordinates:
    In spherical coordinates: tanϕ=x2+y2z\tan \phi = \frac{\sqrt{x^2 + y^2}}{z} For this cone, the angle ϕ\phi (the polar angle from the positive zz-axis) is constant. We are given: ϕ=π6\phi = \frac{\pi}{6} This means the cone has an opening angle of 3030^\circ from the vertical axis.


Would you like further clarification on any part?

Here are five questions you might find interesting:

  1. How do polar and rectangular coordinates relate to each other in general?
  2. How do you derive the equation of a circle from polar to rectangular coordinates?
  3. What other surfaces can be expressed using cylindrical or spherical coordinates?
  4. How does the angle ϕ\phi affect the shape of a cone in spherical coordinates?
  5. How would the equation of a cone change if it was oriented along a different axis?

Tip: Visualizing surfaces in multiple coordinate systems helps solidify your understanding of how geometry and algebra connect.

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Rectangular Coordinates
Spherical Coordinates
Surfaces in 3D
Conic Sections

Formulas

r^2 = x^2 + y^2
x = rcos(θ)
z = sqrt(3x^2 + 3y^2)
tan(φ) = sqrt(x^2 + y^2) / z

Theorems

Conversion between coordinate systems

Suitable Grade Level

College level (Calculus III, Multivariable Calculus)