Math Problem Statement
Which relation is not a function? Question 4 options:
{(–13, –10), (–15, –12), (–11, –8), (–16, 4)}
{(8, 17), (5, 5), (8, –3), (4, –1)}
{(–14, –2), (–10, 6), (–1, 3), (10, 6)}
{(0, –2), (–4, 6), (4, 15), (12, 6)}
Solution
A relation is a function if each input (the first element in each pair) is associated with exactly one output (the second element in each pair). To determine which relation is not a function, we check if any input is associated with more than one output.
Let's examine each relation:
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{(–13, –10), (–15, –12), (–11, –8), (–16, 4)}
- Inputs: –13, –15, –11, –16
- Each input is unique, so this relation is a function.
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{(8, 17), (5, 5), (8, –3), (4, –1)}
- Inputs: 8, 5, 8, 4
- The input 8 is associated with both 17 and –3, so this relation is not a function.
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{(–14, –2), (–10, 6), (–1, 3), (10, 6)}
- Inputs: –14, –10, –1, 10
- Each input is unique, so this relation is a function.
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{(0, –2), (–4, 6), (4, 15), (12, 6)}
- Inputs: 0, –4, 4, 12
- Each input is unique, so this relation is a function.
Conclusion:
The second relation {(8, 17), (5, 5), (8, –3), (4, –1)} is not a function because the input 8 is mapped to two different outputs, 17 and –3.
Would you like more details or have any other questions?
Related Questions:
- What makes a relation a function in general terms?
- Can a function have the same output for different inputs?
- How would you graphically determine if a relation is a function?
- What are real-life examples of functions and non-functions?
- How does the vertical line test help in identifying functions?
Tip: When analyzing a relation, always check if any input has more than one corresponding output to determine if it is a function.
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Math Problem Analysis
Mathematical Concepts
Functions
Relations
Formulas
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Theorems
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Suitable Grade Level
High School
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