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The problem asks which of the following expressions are equal to 6:

1. \(\frac{-48}{-8}\)
2. \(\frac{-48}{8}\)
3. \(\frac{48}{8}\)

Let's solve each one:

1. \(\frac{-48}{-8} = 6\) (Dividing two negative numbers gives a positive result).
2. \(\frac{-48}{8} = -6\) (Dividing a negative number by a positive number gives a negative result).
3. \(\frac{48}{8} = 6\) (Dividing two positive numbers gives a positive result).

So, the expressions that are equal to 6 are:
- \(\frac{-48}{-8}\)
- \(\frac{48}{8}\)

These are the first and third boxes.

Would you like further details on any part of this? Here are 5 related questions to deepen your understanding:

1. How do you determine the sign of a division result when both numbers are negative?
2. Can a division of two negative numbers ever result in a negative value?
3. What happens when the numerator is negative and the denominator is positive?
4. How can you check your answer to division problems involving signs?
5. How does changing the sign of the numerator or denominator affect the result?

**Tip:** Always remember, dividing two numbers with the same sign results in a positive value, while dividing numbers with different signs results in a negative value.

Which of these are equal to 6? Select all that apply.

1. \(\frac{-48}{-8}\)
2. \(\frac{-48}{8}\)
3. \(\frac{48}{8}\)

Learn how to identify which expressions are equal to 6 using division of positive and negative integers. This problem covers important concepts like division rules and the effect of signs in division, suitable for students in Grades 6-7.

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