The graph you provided shows a quadratic curve, which is a parabola, and the problem asks to "identify the x-intercepts of the graph."

X-intercepts:

The x-intercepts are the points where the graph crosses the x-axis. From the image, we can see that the parabola crosses the x-axis at two points:

1. $x = -4$
2. $x = 2$

Therefore, the x-intercepts are: $(-4, 0) \quad \text{and} \quad (2, 0)$

These are the solutions to the equation of the parabola when $y = 0$.

Would you like more details on how to derive the equation of the parabola or any other specific questions?

Related Questions:

1. How can you find the equation of a parabola given the x-intercepts?
2. What role does the vertex play in understanding the parabola?
3. How would you solve the quadratic equation algebraically to find these x-intercepts?
4. What is the difference between a maximum and a minimum vertex in a parabola?
5. How does the direction of the parabola opening (upward or downward) affect the x-intercepts?

Tip:

Remember, for any quadratic equation in the form $ax^2 + bx + c = 0$, the x-intercepts can be found by setting $y = 0$ and solving for $x$.