Math Problem Statement
Identify the stationary points of the function y=f(x)=x^3-3x+2
Solution
To find the stationary points of the function , we need to:
- Differentiate the function to find .
- Set to find the critical points (where the derivative equals zero).
- Solve the equation to find the values of for which the slope is zero (stationary points).
- Verify the nature of these stationary points using the second derivative or by analyzing the sign changes of the first derivative.
Step 1: Find the first derivative
The first derivative of the function is:
Step 2: Set the derivative equal to zero
To find the stationary points, we set :
Step 3: Solve for
Solving the equation:
x^2 - 1 = 0 \\ (x - 1)(x + 1) = 0$$ Thus, $$x = 1$$ or $$x = -1$$. ### Step 4: Verify the nature of the stationary points To determine the nature of the stationary points, we can use the second derivative test. The second derivative of $$f(x)$$ is: $$f''(x) = 6x$$ - For $$x = 1$$: $$f''(1) = 6(1) = 6 > 0$$ Since $$f''(1) > 0$$, the point $$x = 1$$ is a local minimum. - For $$x = -1$$: $$f''(-1) = 6(-1) = -6 < 0$$ Since $$f''(-1) < 0$$, the point $$x = -1$$ is a local maximum. ### Stationary Points: - $$x = 1$$ is a local minimum. - $$x = -1$$ is a local maximum. If you substitute these values back into the original function $$f(x)$$: - At $$x = 1$$: $$f(1) = 1^3 - 3(1) + 2 = 0$$ - At $$x = -1$$: $$f(-1) = (-1)^3 - 3(-1) + 2 = 4$$ Thus, the stationary points are: - $$(1, 0)$$ (local minimum) - $$(-1, 4)$$ (local maximum) --- Would you like more details or have any questions? ### Related Questions: 1. How do we determine if a point is an inflection point? 2. What is the significance of the second derivative in classifying stationary points? 3. Can stationary points also be points of inflection? 4. How does the behavior of a cubic function generally differ from that of a quadratic? 5. How does the third derivative of a function relate to its concavity? ### Tip: Always check the sign of the second derivative around stationary points to confirm whether they are maxima, minima, or points of inflection.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Critical Points
Stationary Points
Formulas
Derivative formula
Second derivative test
Theorems
Second derivative test
Suitable Grade Level
Advanced High School / Undergraduate Level
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