Math Problem Statement

Where is the removable discontinuity of  located?

x = –5

x = –2

x = 2

x = 5

Solution

To identify a removable discontinuity of a function, we examine the function's factored form and determine where a discontinuity can be removed (typically when a factor cancels out).

General Steps:

  1. Identify the function: If given explicitly, factorize the numerator and denominator.
  2. Find common factors: Look for terms in the numerator and denominator that cancel each other.
  3. Determine the removable discontinuity: The value of xx where cancellation occurs is the removable discontinuity.

If you can provide the specific function, I can solve it explicitly. Based on the options provided (x=5,2,2,5x = -5, -2, 2, 5), one of these is likely where the numerator and denominator share a common factor.

Could you provide the full function or confirm if factoring has already been done? This will allow me to pinpoint the discontinuity clearly.


Would you like a detailed breakdown of the process?

Related Questions:

  1. What is a removable discontinuity, and how is it defined?
  2. How does a removable discontinuity differ from a non-removable one?
  3. Can a function have more than one removable discontinuity?
  4. What happens to the graph of a function at a removable discontinuity?
  5. Why is factoring important in identifying removable discontinuities?

Tip:

Always check for cancellation of terms in the numerator and denominator to identify removable discontinuities.

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Math Problem Analysis

Mathematical Concepts

Calculus
Discontinuities
Factoring Rational Functions

Formulas

Factorization of polynomials
Cancellation of common terms in rational functions

Theorems

Definition of removable discontinuity

Suitable Grade Level

Grades 10-12