To determine where the function in the graph is discontinuous, we need to look for points where the function either jumps, has an infinite value, or is undefined. From the graph:

• At $x = -2$, the function is undefined because the graph shows a vertical asymptote.
• At $x = 0$, the function is also undefined due to another vertical asymptote.
• At $x = 2$, the graph shows another vertical asymptote, meaning the function is also discontinuous at this point.

Thus, the function is discontinuous at $x = -2$, $x = 0$, and $x = 2$.

Therefore, the correct answer is B. $x = -2$, $x = 0$, $x = 2$.

Would you like more details about why these points cause discontinuities or have any questions about the graph?

Here are 5 related questions for further exploration:

1. What is a vertical asymptote and how does it cause discontinuity?
2. How can you determine if a function is continuous at a certain point?
3. What other types of discontinuities exist besides those caused by vertical asymptotes?
4. Can a function have removable discontinuities, and what would those look like?
5. How do horizontal asymptotes differ from vertical asymptotes in terms of function behavior?

Tip: When identifying points of discontinuity, always check for vertical asymptotes, jumps, and points where the function is undefined.