Math Problem Statement

The function graphed above is decreasing on the interval and the inflection point is at x = ?

Solution

Let's analyze the graph to address the questions.

1. Decreasing Interval:

A function is decreasing where its slope is negative, meaning the graph goes down as xx increases.

From the graph:

  • The function is increasing until about x=2x = -2.
  • It decreases from x=2x = -2 to around x=2x = 2, as the curve moves downward in this interval.
  • Beyond x=2x = 2, the function starts increasing again.

Thus, the function is decreasing on the interval: 2<x<2-2 < x < 2

2. Inflection Point:

An inflection point is where the concavity of the graph changes, i.e., the curve goes from concave up to concave down, or vice versa.

In the graph:

  • The concavity changes at x=0x = 0, because to the left of x=0x = 0, the graph is concave down, and to the right, it becomes concave up.

Therefore, the inflection point is at: x=0x = 0

Final Answers:

  • The function is decreasing on the interval: 2<x<2-2 < x < 2.
  • The inflection point is at x=0x = 0.

Would you like further details or have any questions?

Here are 5 related questions to expand on this:

  1. What is the increasing interval of the function?
  2. How do you identify local maxima and minima from a graph?
  3. What is the derivative of a function and how is it related to increasing and decreasing intervals?
  4. What are concavity and convexity in terms of second derivatives?
  5. How can we find critical points using the derivative of a function?

Tip: The first derivative of a function helps identify where the function is increasing or decreasing, while the second derivative helps locate inflection points and concavity changes.

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Math Problem Analysis

Mathematical Concepts

Function Behavior
Intervals of Increase and Decrease
Inflection Point
Concavity

Formulas

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Theorems

Inflection Point Theorem
First Derivative Test
Second Derivative Test

Suitable Grade Level

Grades 10-12