**What is *c* in this quadratic equation 6x2 - 2 - x = 0**

In the quadratic equation \(6x^2 - x - 2 = 0\), the standard form of a quadratic equation is:

\[
ax^2 + bx + c = 0
\]

where:
- \(a\) is the coefficient of \(x^2\),
- \(b\) is the coefficient of \(x\),
- \(c\) is the constant term.

For your equation, we can identify:
- \(a = 6\)
- \(b = -1\)
- \(c = -2\)

So, **the value of \(c\) is \(-2\)**.

Would you like more details, or have any questions about quadratic equations?

### Related Questions:
1. How do you solve a quadratic equation using the quadratic formula?
2. How do values of \(a\), \(b\), and \(c\) affect the shape of a parabola?
3. What are some methods for factoring quadratic equations?
4. How do you determine the vertex of a parabola in standard form?
5. Can quadratic equations have complex roots?

**Tip:** The sign of \(c\) affects the vertical shift of the graph of the quadratic equation.

What is *c* in this quadratic equation 6x^2 - 2 - x = 0

Find out how to identify the constant term 'c' in the quadratic equation 6x^2 - x - 2 = 0. This problem explains how to match the equation to the standard form ax^2 + bx + c = 0 and locate each coefficient. Suitable for students in Grades 7-9.

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