Math Problem Statement
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6962 subjects randomly selected from an online group involved with ears. There were 1290 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Question content area bottom Part 1 Identify the null hypothesis and alternative hypothesis. A. Upper H 0: pequals0.2 Upper H 1: pnot equals0.2 B. Upper H 0: pnot equals0.2 Upper H 1: pequals0.2 C. Upper H 0: pgreater than0.2 Upper H 1: pequals0.2 D. Upper H 0: pequals0.2 Upper H 1: pgreater than0.2 E. Upper H 0: pequals0.2 Upper H 1: pless than0.2 Your answer is correct.F. Upper H 0: pless than0.2 Upper H 1: pequals0.2 Part 2 The test statistic is z =
(Round to two decimal places as needed.)
Solution
Part 1: Hypothesis Identification
We are testing whether the return rate of surveys is less than 20%. This indicates that the null hypothesis assumes the return rate is 20%, and the alternative hypothesis suggests that the return rate is less than 20%.
- Null Hypothesis (): The proportion of returned surveys is 20% (i.e., ).
- Alternative Hypothesis (): The proportion of returned surveys is less than 20% (i.e., ).
Thus, the correct hypothesis pair is:
E. ,
Part 2: Calculating the Test Statistic
We will use the normal approximation to the binomial distribution to compute the test statistic.
Step 1: Identify the values
- Sample size () = 1290 (the number of surveys returned)
- Sample proportion () = (the proportion of returned surveys)
- Hypothesized proportion () = 0.20
Step 2: Compute the standard error of the proportion
The standard error () for the sample proportion is calculated using the formula: Substitute and :
Step 3: Calculate the test statistic (z)
The z-test statistic is calculated by the formula: Substitute , , and :
So, the test statistic is z ≈ -3.14.
Summary of Results:
- Null Hypothesis ():
- Alternative Hypothesis ():
- Test Statistic (z): -3.14
Would you like to continue with calculating the p-value or testing the hypothesis further? Let me know if you'd like additional steps or clarifications.
Related Questions:
- How do you compute the p-value for a given z-score?
- What is the interpretation of the p-value in hypothesis testing?
- How would the test change if the significance level was 0.05 instead of 0.01?
- What does the normal approximation to the binomial distribution imply in this context?
- How do you interpret the results if the z-score were greater than the critical value?
Tip: In hypothesis testing, always ensure your sample size is large enough to use the normal approximation, and check if both and .
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Math Problem Analysis
Mathematical Concepts
Hypothesis Testing
Proportions
Normal Distribution Approximation
Z-Tests
Formulas
Standard Error (SE) = sqrt(p0 * (1 - p0) / n)
Test Statistic (z) = (p̂ - p0) / SE
Theorems
Central Limit Theorem (normal approximation to binomial distribution)
Suitable Grade Level
Grades 11-12
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