Math Problem Statement

A sample of 1100 computer chips revealed that 36% of the chips fail in the first 1000 hours of their use. The company's promotional literature claimed that 39% fail in the first 1000 hours of their use. Is there sufficient evidence at the 0.05 level to dispute the company's claim?

Solution

To determine whether there is sufficient evidence at the 0.05 level to dispute the company's claim, we conduct a hypothesis test for a population proportion. Here's a step-by-step explanation:

Step 1: Set up the hypotheses

  • Null Hypothesis (H0H_0): p=0.39p = 0.39 (The population proportion of failed chips is 39%.)
  • Alternative Hypothesis (HaH_a): p0.39p \neq 0.39 (The population proportion of failed chips is not 39%.)

This is a two-tailed test since we are looking for a difference in either direction.

Step 2: Identify the sample statistics

  • Sample proportion (p^\hat{p}) = 36%36\% or 0.360.36
  • Sample size (nn) = 11001100
  • Claimed proportion (p0p_0) = 0.390.39

Step 3: Calculate the test statistic

The test statistic for a proportion is given by:

z=p^p0p0(1p0)nz = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}

Substituting the values:

z=0.360.390.39(10.39)1100z = \frac{0.36 - 0.39}{\sqrt{\frac{0.39(1 - 0.39)}{1100}}}

First, calculate the denominator:

0.39(10.39)1100=0.39×0.611100=0.23791100=0.000216270.0147\sqrt{\frac{0.39(1 - 0.39)}{1100}} = \sqrt{\frac{0.39 \times 0.61}{1100}} = \sqrt{\frac{0.2379}{1100}} = \sqrt{0.00021627} \approx 0.0147

Now calculate the test statistic:

z=0.360.390.0147=0.030.01472.04z = \frac{0.36 - 0.39}{0.0147} = \frac{-0.03}{0.0147} \approx -2.04

Step 4: Determine the critical value

For a two-tailed test at the 0.050.05 significance level, the critical z-values are:

z=±1.96z = \pm 1.96

Step 5: Make a decision

  • If zz-statistic is less than 1.96-1.96 or greater than 1.961.96, we reject H0H_0.
  • Here, z2.04z \approx -2.04, which is less than 1.96-1.96.

Step 6: Conclusion

Since the test statistic falls in the rejection region, we reject the null hypothesis. There is sufficient evidence at the 0.050.05 level to dispute the company's claim that 39% of the chips fail in the first 1000 hours.


Do you want additional details or explanations about this process?

Related Questions:

  1. How is the formula for the test statistic derived?
  2. What would happen if the significance level were changed to 0.010.01?
  3. How does the sample size affect the result of this hypothesis test?
  4. Can we calculate the p-value for this test? If yes, how?
  5. How would a one-tailed test change the outcome of this problem?

Tip:

When conducting hypothesis tests, always visualize the critical regions of the z-distribution to better understand the rejection and non-rejection zones

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Proportions
Standard Normal Distribution

Formulas

z = (p̂ - p₀) / √(p₀(1 - p₀) / n)

Theorems

Central Limit Theorem
Properties of the Standard Normal Distribution

Suitable Grade Level

Undergraduate Statistics or AP Statistics (Grades 11-12)