Math Problem Statement

facebook friends. many people believe that the average number of facebook friends is 140. the population standard deviation is 38.2. A random sample of 38 high school students in a particular country revealed that the average number of facebook friends was 145. at a=0.10, is there suficiente evidence to conclude that the mean number of friends is greater than 140? use the p-value method. state the hypotheses and identify the claim, find the p-value. make the decision. summarize the results

Solution

To solve this hypothesis test using the p-value method, let’s follow the steps systematically:


1. State the Hypotheses and Identify the Claim

  • Null Hypothesis (H0H_0): μ=140\mu = 140 (The mean number of Facebook friends is 140.)
  • Alternative Hypothesis (HaH_a): μ>140\mu > 140 (The mean number of Facebook friends is greater than 140.)
    • This is a right-tailed test.
  • Claim: The alternative hypothesis (HaH_a) represents the claim.

2. Given Data

  • Population standard deviation: σ=38.2\sigma = 38.2
  • Sample size: n=38n = 38
  • Sample mean: xˉ=145\bar{x} = 145
  • Significance level: α=0.10\alpha = 0.10

3. Compute the Test Statistic

The test statistic for a population mean with known standard deviation is calculated using the formula for the zz-score: z=xˉμσnz = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

Substitute the values: z=14514038.238z = \frac{145 - 140}{\frac{38.2}{\sqrt{38}}}

First, compute the denominator: σn=38.23838.26.166.2\frac{\sigma}{\sqrt{n}} = \frac{38.2}{\sqrt{38}} \approx \frac{38.2}{6.16} \approx 6.2

Now compute zz: z=1451406.2=56.20.81z = \frac{145 - 140}{6.2} = \frac{5}{6.2} \approx 0.81

Thus, the test statistic is: z=0.81z = 0.81


4. Find the P-value

Using standard normal distribution tables or a calculator:

  • The p-value is the area to the right of z=0.81z = 0.81 on the standard normal curve.
  • Look up z=0.81z = 0.81 in the z-table: The cumulative probability up to z=0.81z = 0.81 is approximately 0.79100.7910.
  • Therefore: P-value=10.7910=0.209\text{P-value} = 1 - 0.7910 = 0.209

5. Make the Decision

  • Compare the p-value (0.2090.209) to the significance level (α=0.10\alpha = 0.10):
    • 0.209>0.100.209 > 0.10: Fail to reject the null hypothesis (H0H_0).

6. Summarize the Results

At the 0.100.10 significance level, there is insufficient evidence to conclude that the mean number of Facebook friends for high school students in this country is greater than 140.


Follow-Up Questions

  1. Why is the test statistic calculated using the population standard deviation instead of the sample standard deviation?
  2. What would happen if the significance level α\alpha were decreased to 0.05?
  3. How does the sample size affect the precision of the test statistic?
  4. Can you explain the importance of the p-value in hypothesis testing?
  5. What does a right-tailed test imply about the claim being made?

Tip: Always visualize the normal curve and mark the critical region and p-value to gain a better intuition for hypothesis tests.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Z-Score
P-Value
Right-Tailed Test

Formulas

z = (x̄ - μ) / (σ / √n)
P-value = 1 - cumulative probability from z-table

Theorems

Central Limit Theorem
Properties of the Normal Distribution

Suitable Grade Level

Grades 11-12 or Undergraduate Introductory Statistics