Math Problem Statement

A drug testing company is testing for marijuana usage. Among 292 tested subjects, results from 27 were wrong (false positives or false negatives). The claim is that less than 10% of test results are wrong, and the test is conducted at a 0.01 significance level.

Solution

The uploaded image contains a statistics problem about hypothesis testing. Let’s break it down step by step:


Problem:

A drug testing company is testing for marijuana usage. Among 292 tested subjects, results from 27 were wrong (false positives or false negatives). The claim is that less than 10% of test results are wrong, and the test is conducted at a 0.01 significance level.

  1. Null Hypothesis (H0H_0) and Alternative Hypothesis (H1H_1):

    • From the question, the null hypothesis (H0H_0) assumes the proportion of wrong results (pp) is equal to 0.1 (10%).
    • The alternative hypothesis (H1H_1) claims that the proportion of wrong results (pp) is less than 0.1.

    Thus, the correct option is: H0:p=0.1andH1:p<0.1H_0: p = 0.1 \quad \text{and} \quad H_1: p < 0.1

  2. Identify the Test Statistic: To compute the test statistic, we use the formula for a z-test for proportions: z=p^p0p0(1p0)nz = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0 (1 - p_0)}{n}}} Where:

    • p^=xn=27292\hat{p} = \frac{x}{n} = \frac{27}{292}, the sample proportion of wrong results.
    • p0=0.1p_0 = 0.1, the proportion under the null hypothesis.
    • n=292n = 292, the total number of subjects.

Step 1: Calculate p^\hat{p}:

p^=272920.09247\hat{p} = \frac{27}{292} \approx 0.09247


Step 2: Compute the Standard Error:

Standard Error=p0(1p0)n=0.1(10.1)292=0.092920.01751\text{Standard Error} = \sqrt{\frac{p_0 (1 - p_0)}{n}} = \sqrt{\frac{0.1 (1 - 0.1)}{292}} = \sqrt{\frac{0.09}{292}} \approx 0.01751


Step 3: Compute the Test Statistic (zz):

z=p^p0Standard Error=0.092470.10.017510.007530.017510.43z = \frac{\hat{p} - p_0}{\text{Standard Error}} = \frac{0.09247 - 0.1}{0.01751} \approx \frac{-0.00753}{0.01751} \approx -0.43


Final Answer:

The test statistic is approximately: z0.43z \approx -0.43


Would you like a detailed explanation of the interpretation of this result, or do you have specific questions?


5 Follow-Up Questions:

  1. What does the calculated zz-value imply in terms of hypothesis testing?
  2. How do we determine the p-value associated with this zz-value?
  3. What is the conclusion of the test at the 0.01 significance level?
  4. How would the hypotheses change if the claim was "more than 10% of test results are wrong"?
  5. Why do we use a z-test for this type of proportion problem instead of a t-test?

Tip:

When computing standard error in hypothesis tests, always ensure that np0n \cdot p_0 and n(1p0)n \cdot (1 - p_0) are greater than 5 for the approximation to the normal distribution to be valid.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Proportions
Z-Test

Formulas

z = (\hat{p} - p_0) / sqrt((p_0 * (1 - p_0)) / n)
\hat{p} = x / n
Standard Error = sqrt((p_0 * (1 - p_0)) / n)

Theorems

Z-Test for Proportions

Suitable Grade Level

Grades 11-12