Math Problem Statement

Suppose 227 subjects are treated with a drug that is used to treat pain and 51 of them developed nausea. Use a 0.01 significance level to test the claim that more than 20​% of users develop nausea. Question content area bottom Part 1 Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Upper H 0​: pequals0.20 Upper H 1​: pless than0.20 B. Upper H 0​: pequals0.20 Upper H 1​: pnot equals0.20 C. Upper H 0​: pequals0.20 Upper H 1​: pgreater than0.20 Your answer is correct.D. Upper H 0​: pgreater than0.20 Upper H 1​: pequals0.20 Part 2 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is    enter your response here. ​(Round to two decimal places as​ needed.)

Solution

Part 1: Identify the Null and Alternative Hypotheses

We are testing whether more than 20% of the subjects develop nausea, which means this is a one-tailed test. The claim being tested corresponds to the alternative hypothesis H1H_1, where p>0.20p > 0.20.

The correct hypotheses are:

  • Null hypothesis H0H_0: p=0.20p = 0.20
  • Alternative hypothesis H1H_1: p>0.20p > 0.20

The correct answer is: C. H0:p=0.20H_0: p = 0.20, H1:p>0.20H_1: p > 0.20


Part 2: Calculate the Test Statistic

We are performing a one-proportion z-test. The formula for the z-test statistic is:

z=p^p0p0(1p0)nz = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}

Where:

  • p^=512270.2247\hat{p} = \frac{51}{227} \approx 0.2247 (sample proportion)
  • p0=0.20p_0 = 0.20 (hypothesized proportion)
  • n=227n = 227 (sample size)

Step 1: Compute the Standard Error

SE=p0(1p0)n=0.20×(10.20)227=0.16227=0.0007040.0265\text{SE} = \sqrt{\frac{p_0(1 - p_0)}{n}} = \sqrt{\frac{0.20 \times (1 - 0.20)}{227}} = \sqrt{\frac{0.16}{227}} = \sqrt{0.000704} \approx 0.0265


Step 2: Compute the Test Statistic

z=0.22470.200.0265=0.02470.02650.93z = \frac{0.2247 - 0.20}{0.0265} = \frac{0.0247}{0.0265} \approx 0.93


Final Answer

The test statistic for this hypothesis test is:

z0.93z \approx 0.93


Let me know if you have questions or need further clarifications!
Here are five related questions you may find helpful:

  1. How do you determine the critical value for a one-tailed z-test at the 0.01 significance level?
  2. How is the p-value found from a z-score in hypothesis testing?
  3. What assumptions must be satisfied for a one-proportion z-test to be valid?
  4. How would the test change if the sample size or proportion of nausea cases were different?
  5. What is the difference between a one-tailed and two-tailed hypothesis test?

Tip: Always compare the calculated z-value to the critical z-value to determine whether to reject the null hypothesis.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Proportions
Z-Test

Formulas

Z-test statistic formula: z = (p̂ - p₀) / √[p₀(1 - p₀) / n]
Standard error: SE = √[p₀(1 - p₀) / n]

Theorems

Central Limit Theorem
One-Proportion Z-Test

Suitable Grade Level

Undergraduate Statistics or AP Statistics