Math Problem Statement

A doctor is concerned that nausea may be a side effect of Tamiflu, but it is not certain because nausea is common for people who have the flu. She researched some past studies and found that about 38% of people who get the flu and do not use Tamiflu experience nausea. She then collected data on 1974 patients who were taking Tamiflu, and found that 712 experienced nausea. Use a 0.1 significance level to test the claim that the percentage of people who take Tamiflu for the relief of flu symptoms and experience nausea is 38%.

Solution

Let's go through each part of this question and verify or clarify the answers provided. The question involves hypothesis testing to determine if there is sufficient evidence to suggest that nausea is a side effect of Tamiflu, based on a sample of patients.

Problem Breakdown

  1. Type of Test: This is a test for a proportion because we are testing the percentage of people experiencing nausea, which is a categorical outcome.

  2. Evidence for the Test:

    • Conditions for a Proportion Test:
      • The condition np5np \geq 5 and nq5nq \geq 5 must be met for the sample size to approximate a normal distribution, which justifies a z-test for proportions.
      • The sample size is large (n=1974n = 1974), meeting the requirement of n>30n > 30.
    • Answered correctly: np5np \geq 5 and nq5nq \geq 5, and "The sample size is larger than 30".
  3. Hypotheses:

    • Null Hypothesis H0H_0: The null hypothesis is that the proportion of people experiencing nausea is 38% (0.38).
    • Alternative Hypothesis H1H_1: The alternative hypothesis is that the proportion is not equal to 0.38, implying a two-tailed test.
  4. Location of the Claim:

    • The null hypothesis represents the claim that the proportion of people experiencing nausea is 38%.
  5. Test Statistic:

    • The test statistic zz calculated as 1.756-1.756.
  6. P-Value:

    • For z=1.756z = -1.756, the p-value is 0.0784.
  7. Decision:

    • With a significance level (α\alpha) of 0.01, the p-value (0.0784) is greater than α\alpha, so we fail to reject the null hypothesis.
  8. Interpretation:

    • There is insufficient evidence at the 0.01 significance level to conclude that the percentage of people who experience nausea differs from 38%.

Would you like further clarification on any of these points or the calculations involved?

Follow-up Questions:

  1. What is the formula for calculating the z-score in a proportion hypothesis test?
  2. How is the p-value interpreted in hypothesis testing?
  3. Why is it important to verify the conditions for a proportion test?
  4. What would change if the significance level was 0.05 instead of 0.01?
  5. Can you explain the difference between a one-tailed and two-tailed test?

Tip:

When testing hypotheses, always check the assumptions and conditions for the test to ensure accurate results.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Proportions
Z-test

Formulas

z = (p̂ - p) / sqrt((p * (1 - p)) / n)
P-value calculation

Theorems

Central Limit Theorem (for normal approximation of proportions)

Suitable Grade Level

College Statistics or Advanced High School