Math Problem Statement

H0 : ρ =0 H1 : ρ ≠ 0 rn α =0.18=217=0.02 T-Distribution Table a. Calculate the test statistic. t= 0.000 Round to three decimal places if necessary b. Determine the critical value(s) for the hypothesis test. + c. Conclude whether to reject the null hypothesis or not based on the test statistic. Reject Fail to Reject

Solution

To solve the given hypothesis test, let's go through the steps in detail:

Step 1: Calculate the Test Statistic

The test statistic for testing the correlation coefficient (ρ) can be calculated using the following formula:

t=rn21r2t = \frac{r\sqrt{n-2}}{\sqrt{1-r^2}}

Given:

  • Sample correlation coefficient r=0.18r = 0.18
  • Sample size n=217n = 217

Let's substitute these values into the formula:

t=0.18217210.182t = \frac{0.18 \sqrt{217 - 2}}{\sqrt{1 - 0.18^2}} t=0.1821510.0324t = \frac{0.18 \sqrt{215}}{\sqrt{1 - 0.0324}} t=0.182150.9676t = \frac{0.18 \sqrt{215}}{\sqrt{0.9676}} t=0.18×14.66287829840.9836612304t = \frac{0.18 \times 14.6628782984}{0.9836612304} t=2.63931809370.9836612304t = \frac{2.6393180937}{0.9836612304} t2.684t \approx 2.684

So, the test statistic is:

t2.684t \approx 2.684

Step 2: Determine the Critical Value(s) for the Hypothesis Test

The critical values for a two-tailed test can be found using the t-distribution table. For a two-tailed test with a significance level α=0.02\alpha = 0.02 and degrees of freedom df=n2=215df = n - 2 = 215, we need to find the critical t-values that correspond to α/2=0.01\alpha/2 = 0.01 in each tail.

Looking up the t-distribution table or using a calculator for df=215df = 215 and α/2=0.01\alpha/2 = 0.01, we get:

tcritical±2.326t_{\text{critical}} \approx \pm 2.326

Step 3: Conclude Whether to Reject the Null Hypothesis or Not

We compare the calculated test statistic t2.684t \approx 2.684 with the critical value tcritical=±2.326t_{\text{critical}} = \pm 2.326:

  • Since 2.684>2.326|2.684| > 2.326, we reject the null hypothesis H0H_0.

Therefore, based on the test statistic, we reject the null hypothesis.

Summary

a. The test statistic is approximately t=2.684t = 2.684.

b. The critical values are ±2.326\pm 2.326.

c. Since the test statistic falls outside the range of the critical values, we reject the null hypothesis H0H_0.

Would you like more details or have any questions?


Related Questions:

  1. What is the formula for the test statistic used in testing correlation coefficients?
  2. How do you interpret the critical values in hypothesis testing?
  3. What does it mean to reject the null hypothesis in the context of correlation?
  4. How can the degrees of freedom affect the critical value in a t-test?
  5. What is the significance level in hypothesis testing, and how is it chosen?
  6. How would the test statistic change if the sample size were smaller?
  7. What is the impact of a higher correlation coefficient on the test statistic?
  8. How do you find the critical values using a t-distribution table?

Tip: Always check the degrees of freedom and significance level when looking up critical values in a t-distribution table.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Correlation Coefficient
T-Distribution

Formulas

Test Statistic for Correlation Coefficient

Theorems

-

Suitable Grade Level

Advanced