Math Problem Statement

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Topic 5 Homework (Nonadaptive) Question 11 of 21 (1 point)|Question Attempt: 1 of Unlimited

Dennis

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Question 11 A very large company is interested in its employees' productivity. The company reports from its historical data that its employees spend a mean of 122 minutes per employee (on a typical day) dealing with email. To test this claim, an independent consultant chooses 22 employees at random and finds that those employees spend a sample mean of 119 minutes dealing with email, with a sample standard deviation of 12 minutes. Assume that the population of amounts of time employees spend dealing with email is approximately normally distributed.

Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that μ, the mean number of minutes employees spend dealing with email, is equal to 122.

(a) State the null hypothesis H0 and the alternative hypothesis H1 that you would use for the test.

H0:

H1:

(b)Perform a t test and find the p-value. Here is some information to help you with your t test. The value of the test statistic is given by =t−xμsn. The p-value is two times the area under the curve to the left of the value of the test statistic. Student's t Distribution Step 1: Enter the number of degrees of freedom.

Step 2: Select one-tailed or two-tailed. One-tailed Two-tailed Step 3: Enter the test statistic. (Round to 3 decimal places.)

Step 4: Shade the area represented by the p-value.

Step 5: Enter the p-value. (Round to 3 decimal places.)

0.10.20.30.41−12−23−3

(c)Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the company. Conclusion:

Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 122.

Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 122.

Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 122.

Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to reject the claim that the mean number of minutes employees spend dealing with email is equal to 122.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
t-Distribution
Statistical Significance
Two-tailed Test

Formulas

t = (x̄ - μ) / (s / √n)
Degrees of freedom: df = n - 1

Theorems

t-test for hypothesis testing
p-value interpretation

Suitable Grade Level

College Level (Statistics Course)