Math Problem Statement

Include p value

In 2013, the Gallup Poll asked 1031 U.S. adults whether they believed that people should pay sales tax on items purchased over the internet. Of these, 443 said they supported such a tax. Does the survey provide convincing evidence that less than 45% of U.S. adults favor an internet sales tax? Use the α = 0.05 level of significance and the p-value method.

Solution

To address this problem, we are testing whether the proportion of U.S. adults who support an internet sales tax is less than 45% using a hypothesis test.


Step 1: Define the hypotheses

  • Null Hypothesis (H0H_0): p=0.45p = 0.45
    (The proportion of U.S. adults who support the internet sales tax is 45%.)

  • Alternative Hypothesis (H1H_1): p<0.45p < 0.45
    (The proportion of U.S. adults who support the internet sales tax is less than 45%.)

This is a left-tailed test because we are testing if the proportion is less than 45%.


Step 2: Calculate the test statistic

We will use the sample proportion (p^\hat{p}) and perform a z-test for a proportion.

Given:

  • Sample size (nn) = 1031
  • Number of successes = 443
    So, p^=44310310.4297\hat{p} = \frac{443}{1031} \approx 0.4297
  • Hypothesized proportion (p0p_0) = 0.45
  • Significance level (α\alpha) = 0.05

Formula for the z-test statistic:

z=p^p0p0(1p0)nz = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0 (1 - p_0)}{n}}}

Substitute the values: z=0.42970.450.45(10.45)1031z = \frac{0.4297 - 0.45}{\sqrt{\frac{0.45 (1 - 0.45)}{1031}}} z=0.02030.450.551031z = \frac{-0.0203}{\sqrt{\frac{0.45 \cdot 0.55}{1031}}} z=0.02030.00023955z = \frac{-0.0203}{\sqrt{0.00023955}} z0.02030.015481.31z \approx \frac{-0.0203}{0.01548} \approx -1.31


Step 3: Find the p-value

Using a z-table or calculator, find the p-value for z=1.31z = -1.31:

  • For z=1.31z = -1.31, the p-value is approximately 0.0951.

Step 4: Conclusion

Compare the p-value with α=0.05\alpha = 0.05:

  • Since 0.0951>0.050.0951 > 0.05, we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to conclude that less than 45% of U.S. adults support an internet sales tax.


Would you like detailed steps for calculating the z-value or finding the p-value? Let me know!

Here are some related questions to expand this concept:

  1. What assumptions must be satisfied for this test to be valid?
  2. How would the conclusion change if the p-value were smaller than α\alpha?
  3. How does the choice of a one-tailed vs. two-tailed test affect the result?
  4. What is the confidence interval for the population proportion based on this data?
  5. How can this test be replicated using a TI-84 Plus calculator?

Tip: Always verify that sample size is large enough for normal approximation when performing hypothesis tests for proportions.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Proportions
Statistical Significance
p-value

Formulas

z = (p̂ - p₀) / √(p₀(1 - p₀) / n)

Theorems

Central Limit Theorem
Properties of the Standard Normal Distribution

Suitable Grade Level

Grades 10-12 or Introductory College Statistics