Math Problem Statement

Could you teach me quadratics and how you factorize them?

Solution

Understanding Quadratics and Factorization

1. What is a Quadratic?

A quadratic equation is a second-degree polynomial, typically written in the form:

ax2+bx+c=0ax^2 + bx + c = 0

Here:

  • aa, bb, and cc are constants (with a0a \neq 0).
  • xx represents the variable.

Examples:

  • x25x+6=0x^2 - 5x + 6 = 0
  • 2x2+7x4=02x^2 + 7x - 4 = 0

2. What Does Factorizing Mean?

Factorizing a quadratic involves rewriting it as a product of two linear factors: ax2+bx+c=(px+q)(rx+s)ax^2 + bx + c = (px + q)(rx + s)

Where:

  • pp, qq, rr, and ss are constants.
  • Expanding the product gives the original quadratic.

3. Steps to Factorize Quadratics


Case 1: Simple Quadratics (a=1)(a = 1)

If a=1a = 1, the quadratic is: x2+bx+cx^2 + bx + c

Steps:

  1. Find two numbers that:

    • Multiply to cc (the constant term).
    • Add to bb (the coefficient of xx).
  2. Write the factors as: x2+bx+c=(x+m)(x+n)x^2 + bx + c = (x + m)(x + n)

Example:

Factorize x25x+6x^2 - 5x + 6:

  1. c=6c = 6, b=5b = -5.
  2. Numbers are 2-2 and 3-3 because:
    • (2)×(3)=6(-2) \times (-3) = 6
    • (2)+(3)=5(-2) + (-3) = -5.
  3. Write as: x25x+6=(x2)(x3)x^2 - 5x + 6 = (x - 2)(x - 3)

Case 2: Quadratics with a1a \neq 1

For quadratics like ax2+bx+cax^2 + bx + c, a>1a > 1:

Steps:

  1. Multiply a×ca \times c.
  2. Find two numbers that:
    • Multiply to aca \cdot c.
    • Add to bb.
  3. Rewrite the middle term bxbx using these numbers.
  4. Group terms and factorize in pairs.
  5. Write the result as a product of two binomials.

Example:

Factorize 2x2+7x+32x^2 + 7x + 3:

  1. ac=2×3=6a \cdot c = 2 \times 3 = 6, b=7b = 7.
  2. Numbers are 66 and 11:
    • 61=66 \cdot 1 = 6, 6+1=76 + 1 = 7.
  3. Rewrite 7x7x as 6x+x6x + x: 2x2+6x+x+32x^2 + 6x + x + 3
  4. Group terms: (2x2+6x)+(x+3)(2x^2 + 6x) + (x + 3)
  5. Factorize each group: 2x(x+3)+1(x+3)2x(x + 3) + 1(x + 3)
  6. Factor out (x+3)(x + 3): (2x+1)(x+3)(2x + 1)(x + 3)

Case 3: Special Cases

  • Perfect Squares: x2+6x+9=(x+3)2x^2 + 6x + 9 = (x + 3)^2
  • Difference of Squares: x216=(x4)(x+4)x^2 - 16 = (x - 4)(x + 4)

Practice Problems:

Try these for yourself:

  1. x2+8x+15x^2 + 8x + 15
  2. 3x2+11x+103x^2 + 11x + 10
  3. x29x^2 - 9
  4. 2x24x62x^2 - 4x - 6
  5. x2+5x+6x^2 + 5x + 6

Tip:

Always check your factors by expanding them! This ensures they simplify back to the original quadratic.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Factorization

Formulas

Quadratic equation formula ax^2 + bx + c = 0
Factorization: ax^2 + bx + c = (px + q)(rx + s)
Perfect square: (x + a)^2
Difference of squares: a^2 - b^2 = (a + b)(a - b)

Theorems

Zero Product Property
Perfect Square Theorem
Difference of Squares Theorem

Suitable Grade Level

Grades 8-10