To solve $(- \frac{1}{3}) + \frac{1}{2}$, we need to find a common denominator:

The least common denominator (LCD) of 3 and 2 is 6.

1. Rewrite both fractions with a denominator of 6: \quad \text{and} \quad \frac{1}{2} = \frac{3}{6}$$
2. Now add the two fractions: $- \frac{2}{6} + \frac{3}{6} = \frac{1}{6}$

So, $(- \frac{1}{3}) + \frac{1}{2} = \frac{1}{6}$.

Would you like more details on this process or have any questions?

Here are some related problems you could try:

1. $\frac{1}{4} - \frac{1}{3}$
2. $\frac{5}{6} + \frac{1}{2}$
3. $\frac{1}{3} - \frac{1}{5}$
4. $- \frac{1}{2} + \frac{2}{5}$
5. $\frac{1}{6} - \frac{1}{2}$

Tip: Always find the least common denominator (LCD) to simplify the addition or subtraction of fractions.