The problem asks to rationalize the square root of $\frac{3}{7}$.

To rationalize this expression, we follow these steps:

Given:

$\sqrt{\frac{3}{7}}$

Step 1: Rewrite the square root as a fraction of square roots.

$\sqrt{\frac{3}{7}} = \frac{\sqrt{3}}{\sqrt{7}}$

Step 2: Multiply both the numerator and denominator by $\sqrt{7}$ to eliminate the square root in the denominator.

$\frac{\sqrt{3}}{\sqrt{7}} \times \frac{\sqrt{7}}{\sqrt{7}} = \frac{\sqrt{3} \cdot \sqrt{7}}{\sqrt{7} \cdot \sqrt{7}} = \frac{\sqrt{21}}{7}$

Final Answer:

The rationalized form of $\sqrt{\frac{3}{7}}$ is: $\frac{\sqrt{21}}{7}$

Let me know if you need more details or have any questions!

Here are 5 related questions to consider:

1. How do you rationalize expressions with cube roots?
2. What is the process to rationalize expressions with multiple radicals in the denominator?
3. How would you rationalize $\frac{1}{\sqrt{5}}$?
4. Can you explain the difference between rational and irrational numbers?
5. How do you handle rationalizing binomials with radicals?

Tip: When rationalizing, always focus on removing the square root from the denominator by multiplying by the conjugate if needed!