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The problem asks to rationalize the square root of \(\frac{3}{7}\).

To rationalize this expression, we follow these steps:

### Given:
\[
\sqrt{\frac{3}{7}}
\]

### Step 1: Rewrite the square root as a fraction of square roots.
\[
\sqrt{\frac{3}{7}} = \frac{\sqrt{3}}{\sqrt{7}}
\]

### Step 2: Multiply both the numerator and denominator by \(\sqrt{7}\) to eliminate the square root in the denominator.
\[
\frac{\sqrt{3}}{\sqrt{7}} \times \frac{\sqrt{7}}{\sqrt{7}} = \frac{\sqrt{3} \cdot \sqrt{7}}{\sqrt{7} \cdot \sqrt{7}} = \frac{\sqrt{21}}{7}
\]

### Final Answer:
The rationalized form of \(\sqrt{\frac{3}{7}}\) is:
\[
\frac{\sqrt{21}}{7}
\]

Let me know if you need more details or have any questions!

Here are 5 related questions to consider:
1. How do you rationalize expressions with cube roots?
2. What is the process to rationalize expressions with multiple radicals in the denominator?
3. How would you rationalize \(\frac{1}{\sqrt{5}}\)?
4. Can you explain the difference between rational and irrational numbers?
5. How do you handle rationalizing binomials with radicals?

**Tip**: When rationalizing, always focus on removing the square root from the denominator by multiplying by the conjugate if needed!

Learn how to rationalize the square root of 3/7 with step-by-step instructions. This problem involves key algebraic concepts, including simplifying radicals and rationalizing denominators. Suitable for students in Grades 9-11.

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