The problem shown in the image asks to rationalize the expression $\frac{4}{\sqrt{3}}$.

Steps to Rationalize:

1. Multiply the numerator and denominator by $\sqrt{3}$: $\frac{4}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{4\sqrt{3}}{(\sqrt{3})^2}$

2. Simplify: Since $(\sqrt{3})^2 = 3$, the expression becomes: $\frac{4\sqrt{3}}{3}$

Thus, the rationalized form of $\frac{4}{\sqrt{3}}$ is: $\frac{4\sqrt{3}}{3}$

Would you like more details or have any questions?

Here are 5 related questions:

1. How do you rationalize an expression with a cube root in the denominator?
2. What is the significance of rationalizing the denominator in mathematics?
3. How would you rationalize $\frac{5}{\sqrt{2}}$?
4. Can the numerator also contain a square root during rationalization?
5. How would you handle the rationalization if the denominator had a binomial expression like $1 + \sqrt{2}$?

Tip: When rationalizing the denominator, multiplying by the conjugate is useful if there is a binomial expression like $a + \sqrt{b}$.