Math Problem Statement

For the function, find the points on the graph at which the tangent line is horizontal. If none exist, state that fact. The function is f(x) = 2x^2 - 3x + 3.

Solution

To solve this problem, we are asked to find the points on the graph of the function f(x)=2x23x+3f(x) = 2x^2 - 3x + 3 where the tangent line is horizontal. A tangent line is horizontal when its slope is zero. The slope of the tangent line is given by the derivative of the function f(x)f(x).

Steps:

  1. Find the derivative of f(x)f(x):

    The derivative of the function f(x)=2x23x+3f(x) = 2x^2 - 3x + 3 is: f(x)=ddx(2x23x+3)f'(x) = \frac{d}{dx}(2x^2 - 3x + 3) Using basic differentiation rules: f(x)=4x3f'(x) = 4x - 3

  2. Set the derivative equal to 0:

    To find where the tangent line is horizontal, we set the derivative equal to zero and solve for xx: 4x3=04x - 3 = 0 Solving for xx: 4x=34x = 3 x=34x = \frac{3}{4}

  3. Find the corresponding yy-coordinate:

    To find the point where the tangent is horizontal, substitute x=34x = \frac{3}{4} into the original function: f(34)=2(34)23(34)+3f\left(\frac{3}{4}\right) = 2\left(\frac{3}{4}\right)^2 - 3\left(\frac{3}{4}\right) + 3 Simplifying: f(34)=2(916)94+3f\left(\frac{3}{4}\right) = 2\left(\frac{9}{16}\right) - \frac{9}{4} + 3 f(34)=181694+3=98188+248f\left(\frac{3}{4}\right) = \frac{18}{16} - \frac{9}{4} + 3 = \frac{9}{8} - \frac{18}{8} + \frac{24}{8} f(34)=158f\left(\frac{3}{4}\right) = \frac{15}{8}

Thus, the point where the tangent line is horizontal is (34,158)\left( \frac{3}{4}, \frac{15}{8} \right).

Final Answer:

The point where the tangent line is horizontal is (34,158)\left( \frac{3}{4}, \frac{15}{8} \right).


Would you like more details on any part of the solution or have any questions?

Here are 5 related questions to consider:

  1. How do you find the derivative of higher-order polynomials?
  2. What is the geometric interpretation of a horizontal tangent line?
  3. How does the shape of the graph change near points where the tangent is horizontal?
  4. What if a function has multiple points where the tangent is horizontal?
  5. How do you determine if a critical point is a maximum, minimum, or neither?

Tip: The derivative represents the slope of the tangent line at any point on a function, and setting it equal to zero can help find important points like maxima, minima, or points of inflection.

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Math Problem Analysis

Mathematical Concepts

Calculus
Differentiation
Quadratic Functions

Formulas

f'(x) = 4x - 3

Theorems

Derivative of a polynomial function
Setting the derivative equal to zero to find horizontal tangents

Suitable Grade Level

Grades 11-12