Math Problem Statement
What is the new function resulting from applying a horizontal shrink by 1/3 to f(x) = |x - 1| + 3?
Solution
To apply a horizontal shrink by a factor of 1/3 to the function , we need to adjust the -variable in a specific way.
Horizontal Shrink:
A horizontal shrink by a factor of means that every -coordinate in the graph of the function is scaled by a factor of 3. This is equivalent to replacing with in the function.
Applying the transformation:
-
Start with the original function:
-
Apply the horizontal shrink by replacing with :
Final result:
The new function after the horizontal shrink is:
This is the function resulting from applying the horizontal shrink by a factor of to the original function .
Would you like a more detailed explanation of horizontal transformations, or have any other questions on this?
Here are some related questions to explore further:
- How do vertical and horizontal shifts affect the graph of a function?
- What would happen if we applied a horizontal stretch instead of a shrink?
- How can we transform other absolute value functions?
- What is the difference between a horizontal and a vertical transformation?
- How would the horizontal shrink impact the slope of the graph?
Tip: Horizontal transformations (shrinks or stretches) affect the -coordinate directly by replacing with a scaled version, such as for a horizontal shrink.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Horizontal Shrink
Absolute Value Functions
Transformations of Functions
Formulas
f(x) = |x - 1| + 3
f(3x) = |3x - 1| + 3
Theorems
Transformation of Functions
Suitable Grade Level
Grades 8-10
Related Recommendation
Horizontal Shrink Transformation of Absolute Value Function f(x) = |x - 1| + 3
Horizontal Shrink Transformation of the Function f(x) = |x - 3| - 5
Vertical Stretch Transformation of Absolute Value Function |x+1|-1
Transforming the Absolute Value Function |x| to y = |x - 3| - 3
Transformation of Absolute Value Function g(x) = |x + 3| + 2